因此,考虑到我有以下示例:
CompletionStage<String> tokenFuture = getToken();
CompletionStage<CompletionStage<CompletionStage<CompletionStage<Boolean>>>> result = tokenFuture.thenApply(token -> {
WSRequest request = ws.url(url).setHeader("Authorization", "Bearer " + token);
CompletionStage<WSResponse> response = request.post(json);
return response.thenApply(r -> {
if (r.getStatus() == 201) {
return CompletableFuture.supplyAsync(() -> CompletableFuture.supplyAsync(() -> true));
} else {
return getToken().thenApply(t -> {
WSRequest req = ws.url(url).setHeader("Authorization", "Bearer " + t);
return req.post(json).thenApply(b -> b.getStatus() == 201);
});
}
});
});
我的问题是整个
CompletionStage<CompletionStage<CompletionStage<CompletionStage<Boolean>>>>
多嵌套的将来类型。是否可以通过在Scala中使用类似CompletionStage<Boolean>
的方式将其简化为flatMap
,还是有另一种方式来做到这一点? 最佳答案
是的,您正在寻找 thenCompose(fn)
操作:
此方法将一个函数作为参数,该函数接受此完成阶段的结果并返回另一个完成阶段。
因此,您可能需要执行以下操作:
CompletionStage<String> tokenFuture = getToken();
CompletionStage<Boolean> result = tokenFuture.thenCompose(token -> {
WSRequest request = ws.url(url).setHeader("Authorization", "Bearer " + token);
CompletionStage<WSResponse> response = request.post(json);
return response.thenCompose(r -> {
if (r.getStatus() == 201) {
return CompletableFuture.supplyAsync(() -> true);
} else {
return getToken().thenCompose(t -> {
WSRequest req = ws.url(url).setHeader("Authorization", "Bearer " + t);
return req.post(json).thenApply(b -> b.getStatus() == 201);
});
}
});
});
关于java多层嵌套CompletionStage是否等于 "flatMap"?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36307422/