如何在查询的WHERE部分中使用if语句编写SQL查询?
这是我的SQL:
$sql = 'SELECT First, Second,
Third,Fifth, Status, Isik_id, Comments, Code
FROM Persons WHERE Status = 1 && Third = "'.$whoislogged.'" ORDER BY RAND() LIMIT 1';
Third = "'.$whoislogged.'"
是一个来自会话的词。如果$ whoislogged存在并且等于Third,则查询应类似于:
$sql = 'SELECT First, Second, Third,Fifth, Status, Isik_id, Comments, Code
FROM Persons
WHERE Status = 1 && Third = "'.$whoislogged.'" ORDER BY RAND() LIMIT 1';
但是,如果出现$ whoislogged剂量,则查询应类似于:
$sql = 'SELECT First, Second,
Third,Fifth, Status, Isik_id, Comments, Code
FROM Persons WHERE Status = 1 ORDER BY RAND() LIMIT 1';
那么如何将所有这些整合到一个查询中呢?
最佳答案
您可以在查询本身中处理它。
WHERE Status = 1 and if(Third = "'.$whoislogged.'", Third = "'.$whoislogged.'" , 1=1)
条件部分将检查第三个是否与$ whoislogged匹配,如果正确,则添加id作为条件,否则忽略此条件。
关于php - 如何在WHERE中使用if语句在php中编写SQL查询,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/31804008/