我是jquery新手。我遵循此link来学习向右滑动功能。我试图在项目中应用向右滑动功能。但是，向右滑动时它没有任何响应。我想在此页面的任意位置向右滑动时触发向右滑动功能。我不知道哪一部分出了问题。这是我的代码。
<!DOCTYPE html>
<html lang="en-US">
<head>
<title>Tinder-like Marketplace - Mobile Shop Template</title>
<meta charset="utf-8">
<meta content="IE=edge" http-equiv="x-ua-compatible">
<meta content="initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0, user-scalable=no" name="viewport">
<meta content="yes" name="apple-mobile-web-app-capable">
<meta content="yes" name="apple-touch-fullscreen">
<link rel="stylesheet" type="text/css" href="css/style.css">
<link rel="stylesheet" type="text/css" href="css/responsive.css">
<link rel="shortcut icon" href="images/favicon.png">
<link rel="stylesheet" href="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css">
<script src="https://code.jquery.com/jquery-1.11.3.min.js"></script>
<script src="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
<script>
$("body").on("swiperight",function(){
alert("swipe right");
});
</script>
</head>
<body onload="initSwipe()">
<div id="main">
<!-- MAIN PAGE -->
<div id="page">
<!-- CONTENT CONTAINER -->
<div class="content-container">
<!-- Product Header -->
<div class="content-header">
<div class="product-title animated fadeIn" id="productName">
</div><!-- Product title -->
<img src="images/240x240.png" alt="img" />
<!-- Product meta -->
<div class="product-meta animated fadeInUp">
<div class="product-title animated fadeIn">$</div>
<div class="product-title animated fadeIn" id="productPrice">
</div>
</div>
</div>
<div class="line"></div>
</div>
<!-- END CONTENT CONTAINER -->
<div id="swipeLike" class="main-bg"><i class="fa fa-plus"></i></div>
<div id="swipeUnlike" class="main-bg"><i class="fa fa-plus"></i>
</div>
</div>
</div>
<script type="text/javascript" src="js/jquery-3.1.1.js"></script>
<script type="text/javascript" src="js/materialize.min.js"></script>
<script type="text/javascript" src="js/slick.min.js"></script>
<script type="text/javascript" src="js/jquery.slicknav.js"></script>
<script type="text/javascript" src="js/jquery.swipebox.js"></script>
<script type="text/javascript" src="js/custom.js"></script>
<script type="text/javascript" src="js/swipe.js"></script>
</body>
</html>
最佳答案
尝试这样100％工作：
定义swiperight和swipeleft或使用以下命令：
$(document).on('swipeleft', 'body', function(event){ });
$(document).on('swiperight', 'body', function(event){ });
例：
$(document).on('swipeleft', 'body', function(event){
alert("swipeleft");
return false;
});
$(document).on('swiperight', 'body', function(event){
alert("swiperight");
return false;
});<!DOCTYPE html>
<html>
<head>
<title>Swiperight Example</title>
<meta name="viewport" content="width=device-width,height=device-height,minimum-scale=1,maximum-scale=1"/>
<link rel="stylesheet" href="//code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.css" />
<script src="//code.jquery.com/jquery-1.10.1.min.js"></script>
<script src="//code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.js"></script>
</head>
<body>
<p>Try to Swipe Right or Left</p>
</body>
</html>