c - strtol行为不符合预期，c

#include<limits.h>
#include<errno.h>

long output;

errno = 0;
output = strtol(input,NULL,10);
printf("long max = %ld\n",LONG_MAX);
printf("input = %s\n",input);
printf("output = %ld\n",output);
printf("direct call = %ld\n",strtol(input,NULL,10));
if(errno || output >= INT_MAX || output <= INT_MIN) {
    printf("Input was out of range of int, INT_MIN = %d, INT_MAX = %d\n",INT_MIN,INT_MAX);
    printf("Please input an integer within the allowed range:\n");
}

当上面的代码被输入{1'，'2'，'3'，'4'，'5'，'6'，'7'，'8'，'9'，'0'，'1'}
我得到一个输出：

long max = 9223372036854775807
input = 12345678901
output = -539222987
direct call = 3755744309

怎么回事。。。strtol似乎有溢出问题，但没有设置errno

最佳答案

您很可能没有包含必需的<stdio.h>和/或<stdlib.h>标题。
一旦包含以下内容，您的代码就可以正常工作（64位模式下为GCC）：

$ cat t.c
#include<limits.h>
#include<errno.h>
#include<stdlib.h>
#include<stdio.h>

int main (void)
{
    long output;
    char input[] = "12345678901";
    errno = 0;
    output = strtol(input,NULL,10);
    printf("long max = %ld\n",LONG_MAX);
    printf("input = %s\n",input);
    printf("output = %ld\n",output);
    printf("direct call = %ld\n",strtol(input,NULL,10));
    if(errno || output >= INT_MAX || output <= INT_MIN) {
        printf("Input was out of range of int, INT_MIN = %d, INT_MAX = %d\n",INT_MIN,INT_MAX);
        printf("Please input an integer within the allowed range:\n");
    }
    return 0;
}

$ gcc -Wall -Wextra -pedantic t.c
$ ./a.out
long max = 9223372036854775807
input = 12345678901
output = 12345678901
direct call = 12345678901
Input was out of range of int, INT_MIN = -2147483648, INT_MAX = 2147483647
Please input an integer within the allowed range:

顺便说一下，您应该在errno调用之后立即保存strtol，您在strtol和条件之间调用的库函数可能会更改其值。

关于c - strtol行为不符合预期，c，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/7940399/