我有下面的 Pandas 数据框，我试图按降序查找每一行的列名。 A B C DA 1 3 2 1B 2 1 5 0C 1 0 1 9D 2 0 1 2
对于每一行，我试图按排序顺序(降序)获取列索引
我应该得到:B C D AC A B D等等
这可以使用 Pandas 吗？
我正在尝试这样的事情。test[2].sort_index(axis = 0, ascending = True)
12/23 更新
>>> df1
user_handle 1 2 3 4 5 6 8 9 10 12
user_handle
1 6 0 0 1 0 0 0 0 0 0
2 0 95 0 0 1 0 0 0 1 0
3 0 0 2 0 0 0 0 0 0 0
4 1 0 0 12 0 1 0 0 2 0
5 0 1 0 0 9 0 0 0 0 0
6 0 0 0 1 0 14 0 0 1 0
8 0 0 0 0 0 0 4 0 0 0
9 0 0 0 0 0 0 0 12 0 0
10 0 1 0 2 0 1 0 0 49 0
12 0 0 0 0 0 0 0 0 0 2
>>> t1 = np.flip(df1.values.argsort(), 1)
>>> pd.DataFrame(df1.columns[t1])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "python3.6/site-packages/pandas/core/frame.py", line 303, in __init__
dtype=dtype)
File "python3.6/site-packages/pandas/core/frame.py", line 411, in _init_dict
return _arrays_to_mgr(arrays, data_names, index, columns, dtype=dtype)
File "python3.6/site-packages/pandas/core/frame.py", line 5506, in _arrays_to_mgr
return create_block_manager_from_arrays(arrays, arr_names, axes)
File "python3.6/site-packages/pandas/core/internals.py", line 4310, in create_block_manager_from_arrays
mgr = BlockManager(blocks, axes)
File "python3.6/site-packages/pandas/core/internals.py", line 2792, in __init__
(block.ndim, self.ndim))
AssertionError: Number of Block dimensions (3) must equal number of axes (2)
>>>
KeyboardInterrupt
最佳答案
您可以使用 :
temp = np.flip(df.values.argsort(),1)
ndf = pd.DataFrame(df.columns[temp])
0 1 2 3
0 B C D A
1 C A B D
2 D C A B
3 D A C B
关于Python pandas 按降序查找每一行的列名，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/47879262/