我有以下几行:
Message:Polarion commit Mon May 18 06:59:37 CEST 2009
Message:Polarion commit Fri May 15 19:39:45 CEST 2009
Message:424-18: use new variable
Message:Polarion commit Fri May 15 19:29:10 CEST 2009
Message:Polarion commit Fri May 15 19:27:23 CEST 2009
Message:000-00: do something else
Message:Polarion commit Fri May 15 17:50:30 CEST 2009
Message:401-103: added application part
Message:Polarion commit Fri May 15 17:48:46 CEST 2009
Message:Polarion commit Fri May 15 17:42:04 CEST 2009
我想得到所有不包含“Polarion”的行
我该怎么办？
ps:我看到了:
Regex to match against something that is not a specific substring
但这对我没有帮助
pps:我正在tortoiseSVN中尝试选择日志消息，并且我认为“负向后看”存在问题
最佳答案
这种表现将完成这项工作。
^(?:.(?<!Polarion))*$
它使用零宽度的负向后断言来断言该字符串不包含“Polarion”。
^ Anchor to start of string
(?: Non-capturing group
. Match any character
(?<!Polarion) Zero-width negative lookbehind assertion - text to the
left of the current position must not be "Polarion"
)
* Zero or more times
$ Anchor to end of string
The following version will perform the assertion only after a 'n' - maybe this will be faster, maybe slower.
^(?:[^n]*|n(?<!Polarion))*$