我如何获得 future 的约会:

https://github.com/fzaninotto/Faker#fakerproviderdatetime

dateTime($max = 'now')

即将来的日期时间的$ max值应该是多少

最佳答案

尝试传递$max的unix时间戳:

$unixTimestamp = '1461067200'; // = 2016-04-19T12:00:00+00:00 in ISO 8601

echo $faker->dateTime($unixTimestamp);

echo $faker->date('Y-m-d', $unixTimestamp);

// for all rows
$faker->dateTimeBetween('now', $unixTimestamp);

或者将strtotime时间字符串传递给$faker->dateTimeBetween():
// between now and +30y
$faker->dateTimeBetween('now', '+30 years');

关于php - 如何在Faker中获得 future 的约会,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/31076792/

10-11 01:00