c++ - 为什么if语句没有打印出字符串？ cpp

我想在字符串而不是二进制中打印偶数和奇数，以获取true false | 1/0;
为什么输出仍显示 bool(boolean) 值？

int main() {
    printf("enter the two numbers\n");
    int a;
    int b;
    cin >> a >> b;

    string arr[9] = {"one","two","three","four","five","six","seven","eight","nine"};
    for (int i = a; i <= b; i++)
    {
        if(i <=9){
           cout << arr[i-1] << "\n";
        }else{
           cout << ( i%2 == 0)? "even" : "odd"; // print out 1/0 but did not print out the even and odd
           cout << "\n";
        }
    }

    return 0;
}

输出:

enter the two numbers
9 16
nine
1
0
1
0
1
0
1

最佳答案

您缺少将表达式括起来的括号。三元级的优先级低于<<。

cout << (( i%2 == 0)? "even" : "odd");

关于c++ - 为什么if语句没有打印出字符串？ cpp，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/60955636/