我想在我们的代码库中重用一些接受XMLStreamReader
的现有代码,我的应用程序将所需的数据作为w3c文档。
以下示例是最小测试用例:
public static void main(String[] args) throws Exception {
DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = builderFactory.newDocumentBuilder();
Document doc = builder.newDocument();
Element rootElement = doc.createElement("Groups");
doc.appendChild(rootElement);
Element group = doc.createElement("Group");
group.setTextContent("Wibble");
rootElement.appendChild(group);
DOMSource source = new DOMSource(doc);
XMLStreamReader reader = XMLInputFactory.newInstance().createXMLStreamReader(source);
reader.nextTag();
System.out.println("NextTag:" + reader.getName());
}
预期的输出应类似于:
NextTag:Groups
,但将引发以下内容:Exception in thread "main" javax.xml.stream.XMLStreamException: java.net.MalformedURLException
at com.sun.xml.stream.XMLReaderImpl.setInputSource(XMLReaderImpl.java:196)
at com.sun.xml.stream.XMLReaderImpl.<init>(XMLReaderImpl.java:179)
at com.sun.xml.stream.ZephyrParserFactory.createXMLStreamReader(ZephyrParserFactory.java:139)
at Main.main(Main.java:27)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)
Caused by: java.net.MalformedURLException
at java.net.URL.<init>(URL.java:601)
at java.net.URL.<init>(URL.java:464)
at java.net.URL.<init>(URL.java:413)
at com.sun.xml.stream.XMLEntityManager.startEntity(XMLEntityManager.java:762)
at com.sun.xml.stream.XMLEntityManager.startDocumentEntity(XMLEntityManager.java:697)
at com.sun.xml.stream.XMLDocumentScannerImpl.setInputSource(XMLDocumentScannerImpl.java:300)
at com.sun.xml.stream.XMLReaderImpl.setInputSource(XMLReaderImpl.java:193)
... 8
当前正在使用Java 6 update 22。
进一步的信息:ZephyrParserFactory#jaxpSourcetoXMLInputSource的源似乎表明通过处理它的
SystemId
而不是DOMSource的实际内容来转换Source对象。更新:我上面的原始测试用例实际上是使用我的项目类路径运行的,该项目类路径实际上包括JAXB 2.2.1库,而该库又引入了sjsxp 1.0.1。在干净的类路径上运行会产生:
Exception in thread "main" java.lang.UnsupportedOperationException: Cannot create XMLStreamReader or XMLEventReader from a javax.xml.transform.dom.DOMSource
at com.sun.xml.internal.stream.XMLInputFactoryImpl.jaxpSourcetoXMLInputSource(XMLInputFactoryImpl.java:302)
at com.sun.xml.internal.stream.XMLInputFactoryImpl.createXMLStreamReader(XMLInputFactoryImpl.java:145)
符合@Gary Rowe的答案。
最佳答案
这有点令人费解,但是任何支持XQJ API的XQuery实现(例如Saxon)都将允许您提供DOM作为查询“。”的输入,并以XMLStreamReader的形式获得结果。尽管涉及很多重量级机器,但它应该是完全有效的。
借助Saxon,您还可以使用类似以下方法来缩短XQuery方面的功能
Document doc; // the DOM document
XMLStreamReader reader = new PullToStax(PullProvider.makePullProvider(new DocumentWrapper(doc));
但我认为XQJ方法更干净。