我试图用读写文件操作来编写一个简单的debugfs。代码如下。

static ssize_t foo_read(struct file *fp, char __user *user,
                     size_t size, loff_t *loff)
{
    ssize_t retval;

    up_read(&foo_sem);
    retval = simple_read_from_buffer(user, size, loff, fooBuffer,
                                   fooBufferSize);
    down_read(&foo_sem);
    return retval;
}

static ssize_t foo_write(struct file *fp, const char __user *data,
                            size_t size, loff_t *loff)
{
    ssize_t retval;

    pr_debug("foo Write Funcion data %s=,size=%zu\n", data, size);
    up_write(&foo_sem);
    retval = simple_write_to_buffer(fooBuffer, sizeof(fooBuffer)-1, loff,
                                            data, size);
    if (retval > 0) {
            fooBufferSize = size + *loff;
            fooBuffer[fooBufferSize] = '\0';
    }
    down_write(&foo_sem);
    return retval;
}

读写锁初始化为
 static DECLARE_RWSEM(foo_sem);

当我编译代码并在没有锁的情况下运行时,它运行得很好。
然而,当我用锁运行时,程序似乎被调度程序终止了。
[ 8640.104388] INFO: task a.out:6387 blocked for more than 120 seconds.
[ 8640.104398]       Tainted: G           OE  3.17.0-rc5+ #1
[ 8640.104402] "echo 0 > /proc/sys/kernel/hung_task_timeout_secs" disables this message.
[ 8640.104407] a.out           D ffff88007fc14580     0  6387      1 0x00000004
[ 8640.104415]  ffff880075497df0 0000000000000002 ffff88007a0e9900 ffff880075497fd8
[ 8640.104422]  0000000000014580 0000000000014580 ffffffff81c1d480 ffff88007a0e9900
[ 8640.104428]  ffff88007a0e9900 ffffffffa013b018 ffffffffa013b000 ffffffff00000000
[ 8640.104434] Call Trace:
[ 8640.104450]  [<ffffffff8174a8a9>] schedule+0x29/0x70
[ 8640.104460]  [<ffffffff8174d62d>] rwsem_down_write_failed+0x1ed/0x390
[ 8640.104472]  [<ffffffff81381d03>] call_rwsem_down_write_failed+0x13/0x20
[ 8640.104482]  [<ffffffff8174cf7d>] ? down_write+0x2d/0x40
[ 8640.104492]  [<ffffffffa013906e>] foo_write+0x6e/0xa0 [firstmodule]
[ 8640.104503]  [<ffffffff811d42f7>] vfs_write+0xb7/0x1f0
[ 8640.104513]  [<ffffffff811d4e96>] SyS_write+0x46/0xb0
[ 8640.104523]  [<ffffffff8174f47f>] tracesys+0xe1/0xe6

最佳答案

您正在反向使用updown操作。要访问资源时调用down,访问完成后调用up
例如:

down_read(&foo_sem);
retval = simple_read_from_buffer(user, size, loff, fooBuffer,
                               fooBufferSize);
up_read(&foo_sem);

08-27 09:59