我正在尝试为我的一种API编写Junit,在该API中,我使用了Map,如下所示:
Map<String, T> beansMap = ctx.getBeansOfType(clazz);
哪里
ctx = org.springframework.context.ApplicationContext
clazz = Class<T>
我需要模拟
ctx.getBeansOfType(clazz)
并获得我无法执行的该Map<Spring, T>
的返回。 最佳答案
通常,直接从ApplicationContext
检索bean被认为是不好的做法,因为它引入了耦合。
看到为什么https://stackoverflow.com/a/9663099/6604329。
使用字段,构造函数或查找方法注入将消除模拟ApplicationContext
的需要。
无论如何,这是模拟ApplicationContext.getBeansOfType(clazz)
的方法
import org.junit.Test;
import org.mockito.Mockito;
import org.mockito.invocation.InvocationOnMock;
import org.mockito.stubbing.Answer;
import org.springframework.context.ApplicationContext;
import java.util.HashMap;
import java.util.Map;
import static org.junit.Assert.assertFalse;
import static org.mockito.Matchers.any;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.when;
/**
* @author mponomarev
*/
public class ApiTest {
@Test
public void testSomething() throws Exception {
ApplicationContext applicationContext = mock( ApplicationContext.class );
final Map beans = new HashMap();
when( applicationContext.getBeansOfType( any( Class.class ) ) )
.thenAnswer( new Answer<Map<String,Object>>() {
@Override
public Map<String,Object> answer( InvocationOnMock invocation )
throws Throwable {
Class clazz = invocation.getArgumentAt( 0, Class.class );
beans.put( "beanName", mock( clazz ) );
return beans;
}
} );
Api api = new Api( applicationContext );
api.perform();
assertFalse( "beans shouldn't be empty", beans.isEmpty() );
for( Object o : beans.values() ) {
Component component = (Component)o;
Mockito.verify( component ).doSomething();
}
}
public static class Api {
private final Map<String,Component> components;
Api( ApplicationContext applicationContext ) {
this.components = applicationContext.getBeansOfType( Component.class );
}
void perform() {
for( Component component : components.values() ) {
component.doSomething();
}
}
}
public interface Component {
void doSomething();
}
}