ios - 使用NSString作为键和值创建JSON格式

我对JSON的格式要求如下。

{
"first_name" : "XYZ",
"last_name" : "ABC"
}

我在NSString中有值。

NSString strFName = @"XYZ";
NSString strLName = @"ABC";
NSString strKeyFN = @"first_name";
NSString strKeyLN = @"last_name";

我用NSMutableDictionary

NSMutableDictionary* dict = [[NSMutableDictionary alloc]init];
[dict setObject:strFName forKey:strKeyFN];
[dict setObject:strLName forKey:strKeyLN];

然后输出是

{
first_name = XYZ,
last_name = ABC
}

所以我不希望“=”分隔键和值，而是希望“:”分隔键和值

我已经完成了stack overflow questions的大部分工作，但无助于仅在输出中获取“=“

那么请帮忙吗？

最佳答案

这是你的答案:

NSString *strFName = @"XYZ";
NSString *strLName = @"ABC";
NSInteger number = 15;

NSString *strKeyFN = @"first_name";
NSString *strKeyLN = @"last_name";
NSString *numValue = @"Number";

NSMutableDictionary *dic = [[NSMutableDictionary alloc]init];

[dic setObject:strFName forKey:strKeyFN];
[dic setObject:strLName forKey:strKeyLN];
[dic setObject:[NSNumber numberWithInt:number] forKey:numValue];
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:[NSArray arrayWithObject:dic] options:NSJSONWritingPrettyPrinted error:nil];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSLog(@"JSON  %@",jsonString);