authentication - Java-使用HMACSHA256作为PRF的PBKDF2

已经为我的项目创建了一个Login API的任务，并且我应该将PBKDF2和HMACSHA256用作PRF。使用MD5对纯文本密码进行哈希处理，然后将其输入到PBKDF2中以生成派生 key 。问题是，我无法获得与项目文档告诉我的输出相同的输出。

这是Java中的PBKDF2实现:

public class PBKDF2
{
    public static byte[] deriveKey( byte[] password, byte[] salt, int iterationCount, int dkLen )
        throws java.security.NoSuchAlgorithmException, java.security.InvalidKeyException
    {
        SecretKeySpec keyspec = new SecretKeySpec( password, "HmacSHA256" );
        Mac prf = Mac.getInstance( "HmacSHA256" );
        prf.init( keyspec );

        // Note: hLen, dkLen, l, r, T, F, etc. are horrible names for
        //       variables and functions in this day and age, but they
        //       reflect the terse symbols used in RFC 2898 to describe
        //       the PBKDF2 algorithm, which improves validation of the
        //       code vs. the RFC.
        //
        // dklen is expressed in bytes. (16 for a 128-bit key)

        int hLen = prf.getMacLength();   // 20 for SHA1
        int l = Math.max( dkLen, hLen); //  1 for 128bit (16-byte) keys
        int r = dkLen - (l-1)*hLen;      // 16 for 128bit (16-byte) keys
        byte T[] = new byte[l * hLen];
        int ti_offset = 0;
        for (int i = 1; i <= l; i++) {
            F( T, ti_offset, prf, salt, iterationCount, i );
            ti_offset += hLen;
        }

        if (r < hLen) {
            // Incomplete last block
            byte DK[] = new byte[dkLen];
            System.arraycopy(T, 0, DK, 0, dkLen);
            return DK;
        }
        return T;
    }


    private static void F( byte[] dest, int offset, Mac prf, byte[] S, int c, int blockIndex ) {
        final int hLen = prf.getMacLength();
        byte U_r[] = new byte[ hLen ];
        // U0 = S || INT (i);
        byte U_i[] = new byte[S.length + 4];
        System.arraycopy( S, 0, U_i, 0, S.length );
        INT( U_i, S.length, blockIndex );
        for( int i = 0; i < c; i++ ) {
            U_i = prf.doFinal( U_i );
            xor( U_r, U_i );
        }

        System.arraycopy( U_r, 0, dest, offset, hLen );
    }

    private static void xor( byte[] dest, byte[] src ) {
        for( int i = 0; i < dest.length; i++ ) {
            dest[i] ^= src[i];
        }
    }

    private static void INT( byte[] dest, int offset, int i ) {
        dest[offset + 0] = (byte) (i / (256 * 256 * 256));
        dest[offset + 1] = (byte) (i / (256 * 256));
        dest[offset + 2] = (byte) (i / (256));
        dest[offset + 3] = (byte) (i);
    }

    // ctor
    private PBKDF2 () {}

}

我使用在PBKDF2-HMAC-SHA2 test vectors中找到的测试向量来验证实现的正确性，并全部 check out 。我不确定为什么使用MD5哈希密码无法获得相同的结果。

参数:

Salt: 000102030405060708090A0B0C0D0E0F101112131415161718191A1B1C1D1E1F
Iterations Count: 1000
DKLen: 16 (128-bit derived key)

使用“foobar”作为纯文本密码，预期结果是:

PWHash = MD5(PlaintextPassword) = 3858f62230ac3c915f300c664312c63f
PWKey = PBKDF2(PWHash, Salt, IterationsCount, DKLen) = 33C37758EFA6780C5E52FAB3B50F329C

我得到的是:

PWHash = 3858f62230ac3c915f300c664312c63f
PWKey = 0bd0c7d8339df2c66ce4b6e1e91ed3f1

最佳答案

迭代计数应该是4096，而不是1000。