我创建了一个小测试项目来复制该问题。
该项目仅包含pixi.min.js和index.html及其示例中的代码:

http://pixijs.github.io/examples/index.html?s=demos&f=interactivity.js&title=Interactivity

通过浏览器测试按钮时,按钮起作用。
它们还可以在intel-xdk emulate选项卡中使用。

但是,当我转到test选项卡,推送文件,扫描QR码以在iPhone上打开创建的应用程序时,会出现按钮,但触摸事件不起作用。

为什么触摸事件无法在iPhone上触发?

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
</head>
<body style="margin:0; padding: 0; background: #333333;">
    <script src="pixi.min.js"></script>
    <script>
        var renderer = PIXI.autoDetectRenderer(800, 600);
        document.body.appendChild(renderer.view);

        var stage = new PIXI.Container();

        var textureButton = PIXI.Texture.fromImage('images/button.png');
        var textureButtonDown = PIXI.Texture.fromImage('images/button.png');
        var textureButtonOver = PIXI.Texture.fromImage('images/button2.png');

        var buttons = [];

        var buttonPositions = [
            175, 75,
            655, 75,
            410, 325,
            150, 465,
            685, 445
        ];

        var noop = function () {
            //console.log('click');
        };

        for (var i = 0; i < 5; i++)
        {
            var button = new PIXI.Sprite(textureButton);
            button.buttonMode = true;

            button.anchor.set(0.5);

            button.position.x = buttonPositions[i*2];
            button.position.y = buttonPositions[i*2 + 1];
            button.interactive = true;

            button.on('mousedown', onButtonDown)
                .on('touchstart', onButtonDown)
                .on('mouseup', onButtonUp)
                .on('touchend', onButtonUp)
                .on('mouseupoutside', onButtonUp)
                .on('touchendoutside', onButtonUp)
                .on('mouseover', onButtonOver)
                .on('mouseout', onButtonOut);

            button.tap = noop;
            button.click = noop;
            stage.addChild(button);
            buttons.push(button);
        }
        buttons[0].scale.set(1.2);
        buttons[2].rotation = Math.PI / 10;
        buttons[3].scale.set(0.8);
        buttons[4].scale.set(0.8,1.2);
        buttons[4].rotation = Math.PI;

        animate();

        function animate() {
            renderer.render(stage);
            requestAnimationFrame(animate);
        }

        function onButtonDown(){
            this.isdown = true;
            this.texture = textureButtonDown;
            this.alpha = 1;
        }

        function onButtonUp(){
            this.isdown = false;
            if (this.isOver){ this.texture = textureButtonOver;
            }else{ this.texture = textureButton; }
        }

        function onButtonOver(){
            this.isOver = true;

            if (this.isdown){
                return;
            }
            this.texture = textureButtonOver;
        }

        function onButtonOut(){
            this.isOver = false;
            if (this.isdown){ return; }
            this.texture = textureButton;
        }
    </script>
</body>
</html>

最佳答案

var textureButton = PIXI.Texture.fromImage('images/button.png');
var textureButtonDown = PIXI.Texture.fromImage('images/button.png');
var textureButtonOver = PIXI.Texture.fromImage('images/button2.png');

它可以在iPhone上运行,但是由于初始按钮图像textureButtontextureButtonDown相同(button.png),因此您看不到任何事情发生。因此,当您触摸它时,您在屏幕上看不到任何区别。在iPhone上,触摸事件没有hover事件,因此未应用textureButtonOver
但是,当您在模拟器上进行测试时,您正在使用鼠标,因此,当您将鼠标移到textureButtonOver按钮上时,您会在屏幕上看到一个变化。

因此,将textureButtonDown更改为其他图像(button3.png),您将看到它在iPhone上可以正常使用

07-24 14:54