我不确定我在做什么错。我的代码中存在此错误,因此我写了一个简单的示例来尝试确定错误所在。
我有一个ClassA,它依赖于ServiceA和ServiceB两个服务,我正在尝试测试ClassA,并模拟ServiceA和ServiceB。
/**
* Last edited by: $Author: cg $
* on: $Date: 17 Jun 2011 11:36:25 $
* Filename: $RCSfile: ClassA.java,v $
* Revision: $Revision: $
*/
package easy;
import java.util.HashMap;
/**
*
* @version $Revision: $, $Date: 17 Jun 2011 11:36:25 $
*/
public class ClassA {
private ServiceA serviceA;
private ServiceB serviceB;
public ClassA(ServiceA a, ServiceB b) {
this.serviceA = a;
this.serviceB = b;
}
public String process(String p) {
HashMap<String,String> a = serviceA.getServiceA(p);
String ret = serviceB.getServiceB(a);
return ret;
}
}
interface ServiceA{
HashMap<String,String>getServiceA(String s);
}
interface ServiceB{
String getServiceB(HashMap<String,String> p);
}
我的测试如下:
/**
* Last edited by: $Author: cg $
* on: $Date: 17 Jun 2011 11:43:05 $
* Filename: $RCSfile: ClassATest.java,v $
* Revision: $Revision: $
*/
package easy;
import static org.easymock.EasyMock.eq;
import static org.easymock.EasyMock.expect;
import java.util.HashMap;
import junit.framework.Assert;
import org.easymock.EasyMock;
import org.easymock.IMocksControl;
import org.junit.Test;
/**
*
* @version $Revision: $, $Date: 17 Jun 2011 11:43:05 $
*/
public class ClassATest {
@Test
public void testProcess() {
IMocksControl mockery = EasyMock.createControl();
mockery.resetToStrict();
mockery.checkOrder(true);
ServiceA serviceA = EasyMock.createMock("ServiceA",ServiceA.class);
ServiceB serviceB = EasyMock.createMock("ServiceB",ServiceB.class);
ClassA a = new ClassA(serviceA, serviceB);
String myParam = "My Test";
HashMap<String,String> retFromServiceA = new HashMap<String,String>();
retFromServiceA.put("my", "name");
expect(serviceA.getServiceA(eq(myParam))).andReturn(retFromServiceA);
expect(serviceB.getServiceB(retFromServiceA)).andReturn(myParam);
mockery.replay();
String actual = a.process(myParam);
mockery.verify();
Assert.assertEquals(myParam, actual);
}
}
结果失败,因为实际的回报为空。
我尝试调试代码,但我意识到尽管我期望我说我希望ServiceA.getServiceA返回retFromServiceA,但事实并非如此。它返回null。
有任何想法吗?
最佳答案
ServiceS和ServiceS是在不使用嘲笑控件的情况下创建的,因此应使用:
EasyMock.replay(serviceA, serviceB);
在执行处理方法之前