我在静态函数的findViewById
中发现错误。
我的职能是
public static void onYearSelect() {
Spinner yearSelector;
String yearName;
yearSelector = (Spinner) findViewById(R.id.year_submit);
yearName = yearSelector.getSelectedItem().toString();
}
有什么办法可以解决这个错误!
我可以将YearName中的Spinner值存储为String吗
最佳答案
您需要在函数内部添加视图作为参数。
public static void onYearSelect(View view) {
Spinner yearSelector;
yearSelector = (Spinner) view.findViewById(R.id.year_submit);
yearName = yearSelector.getSelectedItem().toString();
}
The view which contains your layout data
。调用该函数时,在此处
onYearSelect(rootView)
添加rootView
具有布局视图。编辑1:
这里是什么视图?
A View in Android is a widget that displays something. Buttons, listviews, imageviews, etc. are all subclasses of View. When you say "change view" I assume you mean change the layout by using setContentView(). This usually only needs to be done once per activity. An Activity is basically what you are referring to as a screen.
您可以阅读更多here。