基于此,可以在waf中将项目的不同variants
构建到不同的输出目录7.2.2。更改变量的输出目录/配置集(https://waf.io/book/#_custom_build_outputs)
但是我不理解如何基于variant
包括不同的文件或目录。
我像这样从waf-book修改了示例,但是我缺少如何构建不同的源文件或包含来自不同目录的文件的示例。
def configure(ctx):
pass
def build(ctx):
if not ctx.variant:
ctx.fatal('call "waf a" or "waf b", and try "waf --help"')
# for variant "a" it should build "a.c" and fpr "b" it should build "b.c"
# for a: bld.program(source='a.c', target='app', includes='.')
# for b: bld.program(source='b.c', target='app', includes='.')
from waflib.Build import BuildContext
class a(BuildContext):
cmd = 'a'
variant = 'a'
from waflib.Build import BuildContext
class b(BuildContext):
cmd = 'b'
variant = 'b'
最佳答案
您运行python waf configure
来配置项目。之后,使用命令build_a
和build_b
构建变体
def configure(ctx):
load('compiler_c')
def build(bld):
if not bld.variant:
bld.fatal('call "waf build_a" or "waf build_b", and try "waf --help"')
if bld.variant == 'a':
bld.program(source='a.c', target='app', includes='.')
elif bld.variant == 'b':
bld.program(source='b.c', target='app', includes='.')
else:
bld.fatal('"')
# create build and clean commands for each build context
from waflib.Build import BuildContext, CleanContext
for x in 'a b'.split():
for y in (BuildContext, CleanContext):
name = y.__name__.replace('Context','').lower()
class tmp(y):
__doc__ = '''executes the {} of {}'''.format(name, x)
cmd = name + '_' + x
variant = x
关于python - 在WAF构建变体中使用其他来源,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47396160/