c# - DayOfWeek获取下一个DayOfWeek(星期一，星期二…星期日)

有没有办法将此代码汇总为1-2行？

我的目标是返回，例如，我有一个DayOfWeek，它是星期一，我想在那之后的第二天(星期二)或那之后的n天。

         switch (_RESETDAY)
        {
            case DayOfWeek.Monday:
                _STARTDAY = DayOfWeek.Tuesday;
                break;
            case DayOfWeek.Tuesday:
                _STARTDAY = DayOfWeek.Wednesday;
                break;
            case DayOfWeek.Wednesday:
                _STARTDAY = DayOfWeek.Thursday;
                break;
            case DayOfWeek.Thursday:
                _STARTDAY = DayOfWeek.Friday;
                break;
            case DayOfWeek.Friday:
                _STARTDAY = DayOfWeek.Saturday;
                break;
            case DayOfWeek.Saturday:
                _STARTDAY = DayOfWeek.Sunday;
                break;
            case DayOfWeek.Sunday:
                _STARTDAY = DayOfWeek.Monday;
                break;
            default:
                _STARTDAY = DayOfWeek.Tuesday;
                break;
        }

最佳答案

根据MSDN，这只是一个int枚举，范围从星期日(0)到星期六(6):



所以简单的数学应该做到这一点:

DayOfWeek nextDay = (DayOfWeek)(((int)_RESETDAY + 1) % 7);

如果需要，请用+ 1替换+ n。

关于c# - DayOfWeek获取下一个DayOfWeek(星期一，星期二…星期日)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32826723/