我有一个像这样的模型:
from wagtail.wagtailcore.models import Page
class Blog(Page):
created = models.DateTimeField(auto_now_add=True)
...
..
现在,默认情况下,如果我的子弹是
hi-there
,则可以在site_url:/hi-there/
上访问该博客文章,但我希望通过site:url/2014/02/05/hi-there/
访问该页面。页面具有多种方法,例如url, url_path
,我应该重写其中的一种,最好的方法是什么练习在w中实现这样的目标? 最佳答案
RoutablePageMixin是当前的实现方法(v2.0 +)。
将模块添加到已安装的应用程序中:
INSTALLED_APPS = [
...
"wagtail.contrib.routable_page",
]
从
wagtail.contrib.routable_page.models.RoutablePageMixin
和wagtail.core.models.Page
继承,然后定义一些视图方法并用wagtail.contrib.routable_page.models.route
装饰器装饰它们:from wagtail.core.models import Page
from wagtail.contrib.routable_page.models import RoutablePageMixin, route
class EventPage(RoutablePageMixin, Page):
...
@route(r'^$') # will override the default Page serving mechanism
def current_events(self, request):
"""
View function for the current events page
"""
...
@route(r'^past/$')
def past_events(self, request):
"""
View function for the past events page
"""
...
# Multiple routes!
@route(r'^year/(\d+)/$')
@route(r'^year/current/$')
def events_for_year(self, request, year=None):
"""
View function for the events for year page
"""
...
关于django - Wagtail模型的自定义URL,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/25240599/