android - 创建一个 float 弹出列表

我想创建一个弹出窗口，就像下面给出的链接。我以为它会使用QuickContactBabage，但事实并非如此。只是不知道如何创造它。
image link http://cdn3.staztic.com/screenshots/android-swim-32-2.jpg
提前谢谢

最佳答案

通过扩展PopupWindow您可以做任何您需要的事情，如您的要求。下面是的主代码，popWindow显示了进程。

ActionItem nextItem     = new ActionItem(ID_DOWN, "Next", getResources().getDrawable(R.drawable.menu_down_arrow));
ActionItem prevItem     = new ActionItem(ID_UP, "Prev", getResources().getDrawable(R.drawable.menu_up_arrow));
ActionItem searchItem   = new ActionItem(ID_SEARCH, "Find", getResources().getDrawable(R.drawable.menu_search));
ActionItem infoItem     = new ActionItem(ID_INFO, "Info", getResources().getDrawable(R.drawable.menu_info));
ActionItem eraseItem    = new ActionItem(ID_ERASE, "Clear", getResources().getDrawable(R.drawable.menu_eraser));
ActionItem okItem       = new ActionItem(ID_OK, "OK", getResources().getDrawable(R.drawable.menu_ok));

//use setSticky(true) to disable QuickAction dialog being dismissed after an item is clicked
prevItem.setSticky(true);
nextItem.setSticky(true);

//create QuickAction. Use QuickAction.VERTICAL or QuickAction.HORIZONTAL param to define layout
//orientation
final QuickAction quickAction = new QuickAction(this, QuickAction.VERTICAL);

//add action items into QuickAction
quickAction.addActionItem(nextItem);
quickAction.addActionItem(prevItem);
quickAction.addActionItem(searchItem);
quickAction.addActionItem(infoItem);
quickAction.addActionItem(eraseItem);
quickAction.addActionItem(okItem);

通过尝试exmample，您将得到如下输出-
另外，请看这里NewQuickAction3D