我想在目标日期起2天前触发通知。目前,我正在使用以下代码来触发通知,但是有确切的方法在目标日期起2天前触发通知。
NSString *frstdate = [[calenderarray objectAtIndex:k] objectForKey:@"date"];
NSLog(@"frstdate..%@",frstdate);
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyy-MM-dd"];
NSDate *date = [dateFormat dateFromString:frstdate];
NSLog(@"date..%@",date);
NSDate *dateToFire = [[[NSDate alloc] initWithTimeInterval:-24*60*60 sinceDate:date]autorelease];
NSLog(@"dateToFire..%@",dateToFire);
UILocalNotification *localNotif = [[UILocalNotification alloc] init];
if (localNotif == nil)
return;
localNotif.fireDate = itemDate;
localNotif.alertAction = @"View";
localNotif.soundName = UILocalNotificationDefaultSoundName;
localNotif.applicationIconBadgeNumber = 1;
localNotif.userInfo = [NSDictionary dictionaryWithObjectsAndKeys:[NSString stringWithFormat:@"Get Food"], @"foodItem", nil] ;
[[UIApplication sharedApplication] scheduleLocalNotification:localNotif];
[localNotif release];
Thanks in advance.
最佳答案
您应该使用NSCalendar和NSDateComponents进行数学运算-类似于:
NSCalendar* calendar = [NSCalendar currentCalendar];
NSDateComponents* twoDaysAgo = [[NSDateComponents alloc] init];
twoDaysAgo.day = -2;
NSDate* dateToFire = [calendar dateByAddingComponents:twoDaysAgo toDate:date options:0];