我在计算平均值时遇到问题
数组中所有非负数，包括零（含零），否则返回零。以下是我的编码，请帮助我检查哪些部分不正确。谢谢。
public class AverageOfNonNegativeNumbers {
public static double averageOfNumbers(double[] x) throws Exception {
double avg = 0.1;
if (x != null) {
for (double i = 0.1; i < x.length; i++) {
if ( x[i]%2 == 0 ) { //Anyone know how to set avoid calculate for negative numbers?
avg = avg / x[i]; //This code is calculate total average number.
}
}
}
return avg;
}
public static void main(String args[]) {
double x[] = {1.663, -2.1312, 3.13231, 4.124, -5.551, -6.1312, 7.111, 8.222, -9.01};
try {
System.out.println(AverageOfNonNegativeNumbers.averageOfNumbers(x));
} catch (Exception e) {
System.out.println("Error!!!");
}
}
}
最佳答案
定义2个变量来存储非负数的sum和非负数的count。
然后遍历数组并检查每个元素的非负性。如果为负数，则将该值添加到sum并将count递增1。
最后，将sum除以count得到平均值。
public static double averageOfNumbers(double[] x) {
double sum = 0; // Variable to store the sum
int count = 0; // Variable to keep the count
if (x != null) {
for (int i = 0; i < x.length; i++) {
double value = x[i];
if (value >= 0) { // Check if the number is non-negative
sum += value; // Add the value to the current sum
count++; // Increment the count by 1
}
}
}
return (count > 0) ? (sum /count) : 0; // Calculate the average if there were any non-negative numbers
}
关于java - 如何计算数组中所有非负数的平均值，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/58178072/