我试图编写一个复杂的sql查询,但无法获得具有正确值的结果集。coupons
桌上有一些在线优惠券。merchants
表保存商家信息,并与coupons
绑定。coupons.merchant_id
表保存值为branches
和lat
的商家分支(用于计算距离和最近的分支等),并与lng
表绑定。merchants
表格关联branches.merchant_id
和coupons_branches
表格。coupons
桌上有一些特殊的地方,如购物中心等,并与branches
桌相连。
下面是我的桌子结构;
CREATE TABLE IF NOT EXISTS `branches` (
`branch_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`merchant_id` int(11) unsigned NOT NULL DEFAULT '0',
`place_id` smallint(5) unsigned NOT NULL DEFAULT '0',
`branch` varchar(40) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
`address` varchar(255) COLLATE utf8_unicode_ci DEFAULT '',
`postcode` varchar(6) COLLATE utf8_unicode_ci DEFAULT '',
`phone` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`fax` varchar(20) COLLATE utf8_unicode_ci DEFAULT NULL,
`lat` float(10,6) DEFAULT NULL,
`lng` float(10,6) DEFAULT NULL,
`status` tinyint(4) unsigned NOT NULL DEFAULT '1',
PRIMARY KEY (`branch_id`),
KEY `lat` (`lat`),
KEY `lng` (`lng`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
CREATE TABLE IF NOT EXISTS `coupons` (
`coupon_id` mediumint(9) unsigned NOT NULL AUTO_INCREMENT,
`category_id` tinyint(4) unsigned NOT NULL DEFAULT '0',
`merchant_id` mediumint(9) unsigned NOT NULL DEFAULT '0',
`coupon` varchar(200) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
`description` longtext COLLATE utf8_unicode_ci,
`start_date` date DEFAULT NULL,
`end_date` date DEFAULT NULL,
`coupon_usage` int(10) unsigned NOT NULL DEFAULT '0',
`created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`status` enum('active','passive','deleted','preview') COLLATE utf8_unicode_ci NOT NULL DEFAULT 'active',
PRIMARY KEY (`coupon_id`),
KEY `start_date` (`start_date`),
KEY `end_date` (`end_date`),
KEY `merchant_id` (`merchant_id`),
KEY `category_id` (`category_id`),
KEY `status` (`status`),
KEY `created` (`created`),
FULLTEXT KEY `description` (`description`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
CREATE TABLE IF NOT EXISTS `coupons_branches` (
`branch_id` int(11) unsigned NOT NULL DEFAULT '0',
`coupon_id` int(11) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`branch_id`,`coupon_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
CREATE TABLE IF NOT EXISTS `merchants` (
`merchant_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`merchant` varchar(80) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
`website` varchar(150) COLLATE utf8_unicode_ci DEFAULT NULL,
`created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`status` enum('active','passive','deleted') COLLATE utf8_unicode_ci NOT NULL DEFAULT 'passive',
PRIMARY KEY (`merchant_id`),
KEY `status` (`status`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
CREATE TABLE IF NOT EXISTS `places` (
`place_id` smallint(5) unsigned NOT NULL AUTO_INCREMENT,
`city_id` smallint(5) unsigned NOT NULL DEFAULT '0',
`place` varchar(150) COLLATE utf8_unicode_ci DEFAULT NULL,
PRIMARY KEY (`place_id`),
KEY `place` (`place`),
KEY `city_id` (`city_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1 ;
这是我的SQL语句;
SELECT * FROM (SELECT coupons.coupon_id AS c_id, coupons.category_id, coupons.coupon, merchants.merchant_id, merchants.merchant, (((acos(sin((41.02287686 * pi() / 180)) * sin((branches.lat * pi() / 180)) + cos((41.02287686 * pi() / 180)) * cos((branches.lat * pi()/ 180)) * cos(((29.04632806 - branches.lng) * pi() / 180)))) * 180 / pi()) * 60 * 1.1515 * 1.609344) as distance, COUNT(coupons.coupon_id) AS total_coupons
FROM (`coupons`)
INNER JOIN `coupons_branches` ON `coupons`.`coupon_id` = `coupons_branches`.`coupon_id`
RIGHT OUTER JOIN `branches` ON `coupons_branches`.`branch_id` = `branches`.`branch_id`
LEFT OUTER JOIN `merchants` ON `coupons`.`merchant_id` = `merchants`.`merchant_id`
WHERE `coupons`.`status` = 'active'
AND `merchants`.`status` = 'active'
GROUP BY `merchants`.`merchant_id`
HAVING `distance` <= 25000
ORDER BY `merchants`.`merchant`) as T2 GROUP BY c_id ORDER BY merchant
我在查一个商人的全部优惠券。我只想列出那个商人的最新优惠券。我不想列出所有的优惠券。我想先把商家分组,显示商家有多少优惠券。然后在另一页,我会展示属于那个商人的优惠券。
除了
places
列之外,一切都很好。未正确计算“优惠券总数”列。如果我在下面写这样的话,它的计算是正确的。SELECT * FROM (SELECT coupons.coupon_id, coupons.coupon_id AS c_id, coupons.category_id, coupons.coupon, merchants.merchant_id, merchants.merchant, coupons.coupon_usage, COUNT(coupons.coupon_id) AS total_coupons
FROM (`coupons`)
LEFT OUTER JOIN `merchants` ON `coupons`.`merchant_id` = `merchants`.`merchant_id`
WHERE `coupons`.`status` = 'active'
AND `merchants`.`status` = 'active'
GROUP BY `merchants`.`merchant_id`
ORDER BY `merchants`.`merchant`) as T2 GROUP BY c_id ORDER BY merchant
branches
和branches.place_id
表有问题,但我找不到。 最佳答案
尝试将COUNT()
表达式更改为COUNT(DISTINCT coupons.coupon_id)
。如果没有distinct关键字,即使是重复的优惠券也会被计入商家优惠券的总数。我猜你只是在寻找目前分发给分行的优惠券的总数。