我有一个带有Derived1和Derived2派生类的基类以及一个Consumer类。
我想用两个派生类对象创建一个基指针 vector ,然后传递给使用者类,以便它可以使用以下方法获取派生类详细信息
pointervec.at(0).i
我已经为此坚持了很长时间,无法使其正常工作。这是我所拥有的简化版本。我担心围绕创建 vector ,将其传递到线程并访问不同索引的语法。
#include<vector>
#include<thread>
#include<iostream>
using namespace std;
class Base
{
public:
Base() {};
void dosomething() {cout<<i<<endl;}
int i;
};
class Derived1 : public Base
{
public:
Derived1() {i = 5;}
};
class Derived2 : public Base
{
public:
Derived2() {i = 10;}
};
class Consumer
{
public:
Consumer();
void dostuff( vector<Base> &pointervec) {cout<<5<<endl;}
};
int main( int argc, char ** argv )
{
Derived1 derived1;
Derived2 derived2;
vector<Base*>pointervec;
pointervec.push_back(&derived1);
pointervec.push_back(&derived2);
std::thread t1(&Derived1::dosomething, &derived1);
std::thread t2(&Derived2::dosomething, &derived2);
std::thread t3(&Consumer::dostuff, ref(pointervec));
t1.join();
t2.join();
t3.join();
}
最佳答案
为了使您的示例正常工作,需要纠正一些错误。
Consumer::doStuff
是一个非静态成员函数,因此需要Consumer
实例才能对其运行。 Consumer
需要定义的构造函数doStuff
的签名需要采用Base
指针的 vector (对a的引用),而不是Base
对象t3
需要将Consumer
的实例作为其第一个转发参数(以提供this
参数。最终的工作代码:
#include<vector>
#include<thread>
#include<iostream>
using namespace std;
class Base
{
public:
Base() {};
void dosomething() {cout<<i<<endl;}
int i;
};
class Derived1 : public Base
{
public:
Derived1() {i = 5;}
};
class Derived2 : public Base
{
public:
Derived2() {i = 10;}
};
class Consumer
{
public:
Consumer() {}
void dostuff( vector<Base*> &pointervec) {cout<<pointervec.at(0)->i<<endl;}
};
int main( int argc, char ** argv )
{
Derived1 derived1;
Derived2 derived2;
Consumer c;
vector<Base*>pointervec;
pointervec.push_back(&derived1);
pointervec.push_back(&derived2);
std::thread t1(&Derived1::dosomething, &derived1);
std::thread t2(&Derived2::dosomething, &derived2);
std::thread t3(&Consumer::dostuff, &c, ref(pointervec));
t1.join();
t2.join();
t3.join();
}
关于c++ - 将派生类指针的 vector 传递给线程,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/37704024/