这是我的整个代码:
days=["Sunday: ", "Monday: ", "Tuesday: ", "Wednesday: ", "Thursday: ", "Friday: ", "Saturday: "]
demand=[]
temp=[]
demand=[15, 20, 25, 18, 20, 22, 14]
while demand[0]>0 or demand[1]>0 or demand[2]>0 or demand[3]>0 or demand[4]>0 or demand[5]>0 or demand[6]>0:
min1=min(demand)
ind1=demand.index(min1)
temp=demand.copy()
temp[ind1]=100000
min2=min(temp)
ind2=temp.index(min2)
print(min1, ind1, min2, ind2)
for i in range(7):
if i != ind1 and i != ind2:
demand[i]-=1
print(demand)
print(days[0], demand[0]+15, days[1], demand[1]+20, days[2], demand[2]+25, days[3], demand[3]+18, days[4], demand[4]+20, days[5], demand[5]+22, days[6], demand[6]-14)
我想垂直打印最后一个
print
命令,这样最终结果如下:Sunday: 15
Monday: 20
Tuesday: 25
Wednesday: 18
Thursday: 20
Friday: 22
Saturday: 14
最佳答案
一种简单的方法是对print
循环中的每一行使用单独的for
语句:
offsets = [15, 20, 25, 18, 20, 22, -14]
for day in range(7):
print(days[day], demand[day] + offsets[day])