我想使用Jolt(com.bazaarvoice.jolt:jolt-core:0.1.1
和com.bazaarvoice.jolt:json-utils:0.1.1
)连接几个字段。这是一个示例输入记录:
{
"ts": 1572873208.555711,
"uid": "CQXg712bv3ayjojRwd",
"orig_lat": 39.997,
"orig_long": -105.0974,
"resp_lat": 39.0481,
"resp_long": -77.4728
}
...这是Jolt转换:
[
{
"operation": "modify-default-beta",
"spec": {
"orig_location": "=concat(@(1,orig_lat),',',@(1,orig_long))",
"resp_location": "=concat(@(1,resp_lat),',',@(1,resp_long))"
}
}
]
...这是Jolt Transform Demo site转换的输出:
{
"ts" : 1.572873208555711E9,
"uid" : "CQXg712bv3ayjojRwd",
"orig_lat" : 39.997,
"orig_long" : -105.0974,
"resp_lat" : 39.0481,
"resp_long" : -77.4728,
"orig_location" : "39.997,-105.0974",
"resp_location" : "39.0481,-77.4728"
}
我试图以编程方式执行此操作:
String input = "{\"ts\":1572873208.555711,\"uid\":\"CQXg712bv3ayjojRwd\",\"orig_lat\":39.997,\"orig_long\":-105.0974,\"resp_lat\":39.0481,\"resp_long\":-77.4728}";
String JOLT_SPEC_LIST = "[\n" +
" {\n" +
" \"operation\": \"modify-default-beta\",\n" +
" \"spec\": {\n" +
" \"orig_location\": \"=concat(@(1,orig_lat),',',@(1,orig_long))\",\n" +
" \"resp_location\": \"=concat(@(1,resp_lat),',',@(1,resp_long))\"\n" +
" }\n" +
" }\n" +
"]";
Chainr chainr = Chainr.fromSpec(JsonUtils.jsonToList(JOLT_SPEC_LIST));
Object transformed = chainr.transform(input);
transformed
对象应该包含转换后的输出。由于某些原因,输出与输入相同。它不包含两个派生字段。你能看到我做错了吗?
最佳答案
我错误地将字符串传递给了transform方法。应该是Object
。
我使用杰克逊将字符串转换为对象:
ObjectMapper mapper = new ObjectMapper();
Object inputObject = mapper.readValue(input, Object.class);
...,然后将该对象传递给
Chainr.transform()
方法。