c++ - 无法在C++中使用Boost和Eureqa编译程序

因此，我将尝试在Xcode中尝试一个简单的Eureqa API示例，如下所示:
https://code.google.com/p/eureqa-api/

但是，当我尝试编译它时，此行中boost头文件的access.hpp中似乎有一个错误:
...

{
    // note: if you get a compile time error here with a
    // message something like:
    // cannot convert parameter 1 from <file type 1> to <file type 2 &>
    // a likely possible cause is that the class T contains a
    // serialize function - but that serialize function isn't
    // a template and corresponds to a file type different than
    // the class Archive.  To resolve this, don't include an
    // archive type other than that for which the serialization
    // function is defined!!!
    t.serialize(ar, file_version);
}

...
带有一条消息:'std::_ 1::pair'中没有名为'serialize'的成员

为了解决这个问题我该怎么办？

最佳答案

看起来您只想包含标题

#include <boost/serialization/utility.hpp>

定义std::pair<>的序列化。

编辑评论(并回到家)后，我在Linux上使用boost 1.58重现了该问题。确实，编辑eureqa/implementation/connection_impl.h以包括

#include <boost/serialization/utility.hpp>
#include <boost/serialization/nvp.hpp>

解决它:

g++ basic_client.cpp \
    -I/home/sehe/custom/boost/ \
    -I../../ \
    -c -o basic_client.o
g++ basic_client.o \
    /home/sehe/custom/boost/stage/lib/libboost_system.a \
    /home/sehe/custom/boost/stage/lib/libboost_serialization.a \
    /home/sehe/custom/boost/stage/lib/libboost_date_time.a \
    /home/sehe/custom/boost/stage/lib/libboost_thread.a \
    -lpthread  \
    -o basic_client

::_1可能是使用内联 namespace 进行版本控制的库实现(libc++)的产物。