Django 1.5和Python 2.6。
该模型具有clean()
方法,该方法验证job.company_id
必须等于job.location.company_id
我正在尝试为此编写一个测试,但是该测试未通过/未通过测试,而是以模型的clean()
方法中的验证错误消息结束。
这是代码(忽略不相关的位):
在models.py中:
class Job(models.Model):
title = models.CharField(max_length=200, verbose_name="Job title")
company = models.ForeignKey(Company)
location = models.ForeignKey(Location, blank=True, null=True)
def clean(self):
from django.core.exceptions import ValidationError
'''
Location.company_id must equal Job.company_id
'''
if (self.company_id != Location.objects.get(pk=self.location_id).company_id):
raise ValidationError('Location is not valid for company')
在tests.py中:
class job_cannot_have_invalid_location_and_can_have_valid_location(TestCase):
def test_jobs_and_locations(self):
job2 = Job.objects.create(company_id=company2.id)
location1 = Location.objects.create(company_id=company1.id)
job2.location_id = location1.id
self.assertRaises(ValidationError, job2.clean())
当我运行python manage.py test时:
.E.
======================================================================
ERROR: test_jobs_and_locations (companies.tests.job_cannot_have_invalid_location_and_can_have_valid_location)
----------------------------------------------------------------------
Traceback (most recent call last):
File "/home/djangobox/jobboard/companies/tests.py", line 60, in test_jobs_and_locations
self.assertRaises(ValidationError, job2.clean())
File "/home/djangobox/jobboard/companies/models.py", line 151, in clean
raise ValidationError('Location is not valid for company')
ValidationError: [u'Location is not valid for company']
最佳答案
问题是您对assertRaises
的用法。它应该包含异常和可调用对象以进行检查:http://docs.python.org/2/library/unittest.html#unittest.TestCase.assertRaises
但是,您没有传递可调用的job2.clean
,而是传递了可调用的job2.clean()
的返回值。更改为
self.assertRaises(ValidationError, job2.clean)
应该修复异常和您的测试用例。
关于python 2.6-Django TestCase-assertRaises ValidationError clean()方法,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20354385/