我有一个具有动态用户信息的系统。基本上,我有一个具有ID,名称,电子邮件和密码(必需的基本知识)的用户表。而且,如果系统管理员希望添加用户字段,则可以通过在user_fields表中添加新条目来添加用户字段,然后将该字段的数据存储在user_fields_data中。
用户:
id | name | email | password
=============================================
1 | bob smith | [email protected] | asdfasdfasdf
...
user_fields:
id | field
==========
1 | address_1
2 | address_2
...
user_fields_data:
user_id | field_id | value
===============================
1 | 1 | 123 abc st
1 | 2 | suite 314
基本上,我的目标是执行一个查询,以获取所有信息。
array(
'name' => 'bob',
'email' => '[email protected]',
'password' => 'asdfasdfasdf',
'address_1' => '123 abc st',
'address_2' => 'suite 314'
)
我整天将表连接在一起,但是我从来不需要以这种方式(行/列)连接一个表。
提前致谢!
最佳答案
select 'name' as name, name as value from user where id = 1
union all
select 'email', email from user where id = 1
union all
select 'password', password from user where id = 1
union all
select uf.field, ufd.value
from user_fields_data ufd
inner join user_fields uf on ufd.field_id = uf.id
where ufd.user_id = 1
SQL Fiddle Example
输出:
| NAME | VALUE |
-----------------------------
| name | bob smith |
| email | [email protected] |
| password | asdfasdfasdf |
| address_1 | 123 abc st |
| address_2 | suite 314 |
关于php - MySQL联合/联合行与列,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/12287922/