我有一个非常有趣的问题。
在我的一个类中,我声明了一个非常简单的实例方法-(NSDictionary)dictionary;
以这种方式实现:
- (NSDictionary *)dictionary {
return [NSDictionary dictionaryWithObjectsAndKeys:
self.userID, @"id",
self.userName, @"name",
self.userSurname, @"sName",
self.userNickname, @"nName",
self.userPassword, @"pwd",
[NSNumber numberWithDouble:[self.userBirthday timeIntervalSince1970] * 1000], @"birthday",
self.userSex, @"sex",
self.userEmail, @"email",
self.userLanguage, @"locale",
[NSNumber numberWithLongLong:self.userCoin], @"coin",
self.userRate, @"rate",
[NSNumber numberWithDouble:self.userCoordinate.latitude], @"lat",
[NSNumber numberWithDouble:self.userCoordinate.longitude], @"lon",
self.userPlaces, @"userPlaces",
nil];
}
声明此方法后,我的返回字典中没有@“userPlaces”键(self.userPlace很明显是虚荣的,里面装满了对象)。
所以我改变了我的方法,像这样:
- (NSDictionary *)dictionary {
NSMutableDictionary *toReturn = [NSMutableDictionary dictionary];
[toReturn setValue:self.userID forKey:@"id"];
[toReturn setValue:self.userName forKey:@"name"];
[toReturn setValue:self.userSurname forKey:@"sName"];
[toReturn setValue:self.userNickname forKey:@"nName"];
[toReturn setValue:self.userPassword forKey:@"pwd"];
[toReturn setValue:[NSNumber numberWithDouble:[self.userBirthday timeIntervalSince1970] * 1000] forKey:@"birthday"];
[toReturn setValue:self.userSex forKey:@"sex"];
[toReturn setValue:self.userEmail forKey:@"email"];
[toReturn setValue:self.userLanguage forKey:@"locale"];
[toReturn setValue:[NSNumber numberWithLongLong:self.userCoin] forKey:@"coin"];
[toReturn setValue:self.userRate forKey:@"rate"];
[toReturn setValue:[NSNumber numberWithDouble:self.userCoordinate.latitude] forKey:@"lat"];
[toReturn setValue:[NSNumber numberWithDouble:self.userCoordinate.longitude] forKey:@"lon"];
[toReturn setValue:self.userPlaces forKey:@"userPlaces"];
return [NSDictionary dictionaryWithDictionary:toReturn];
}
现在所有键都存在于输出字典中!!!!
这个问题使我疯狂地理解,但是我的问题是...
有什么原因可以使第二种方法比第一种更好?
我没有找到原因。
最佳答案
[NSDictionary dictionaryWithObjectsAndKeys:
在找到nil
值时停止添加对象。
因此,您尝试在第一个代码中添加的对象最有可能是nil。