c++ - 取消此goto语句

从ACM编程竞赛文件中搜索，找到了椰子程序的解决方案:
它有一个goto-如何消除这一点？有没有遵循的模板或过程。
谢谢

/*
1997 East-Central ACM regional programming contest
Held on November 8, 1997
Coconuts, Revisited -- Problem 3
Sample solution by Ed Karrels, [email protected]
November 1997
*/
#include <stdio.h>
/* return 1 if this number of coconuts can be divided up
properly between this number of people */
int SplitCoco(long n_coco, long n_people) {
long i;
for (i=0; i<n_people; i++) {
/* check that the coconuts divide by the number of people
plus one remainder */
    if (n_coco % n_people != 1) return 0;
    /* remove 1 for the monkey, and one person's share */
        n_coco = n_coco - 1 - (n_coco / n_people);
    }
    /* check that the remaining coconuts divide evenly among
    the people */
    return (n_coco % n_people) == 0;
}


int main() {
    long n_coco;
    long n_people;
    long i, j, k;

    FILE *inf = stdin;
    while (fscanf(inf, "%ld", &n_coco), n_coco!=-1) {
    /* starting at the # of coconuts-1, count down until
    a number of people is found that works */
        for (n_people=n_coco-1; n_people > 1; n_people--) {
            if (SplitCoco(n_coco, n_people)) {
                 printf("%ld coconuts, %ld people and 1 monkey\n",
                 n_coco, n_people);
                 goto found;
                 /* OK, so yea, I put a 'goto' in my code :-)
                it was quick and it works. I don't do
                it often, I swear. */
            }
        }
     /* if no number of people greater than 1 works, there is
     no solution */
        printf("%ld coconuts, no solution\n", n_coco);
        found:
    }
    return 0;
}

最佳答案

在您的情况下，您可以创建一个单独的例程来计算while并将goto found替换为return。

通常，您可以将每个goto替换为一个标志和一些while循环。这不会使代码更易于阅读。

关于c++ - 取消此goto语句，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/12340935/