我有JSON列,其中包含JSON数组。我的方案是获取所有记录,其中url的值是
'"example.com/user1"'存在。我无法为此操作编写查询。

Record1
 [
    {
        "id": "1",
        "firstname": "user1",
        "url": "example.com/user1"
    },
    {
        "id": "2",
        "firstname": "user2",
        "url": "example.com/user2"
    }
]
Record2
     [
        {
            "id": "1",
            "firstname": "user3",
            "url": "example.com/user3"
        },
        {
            "id": "2",
            "firstname": "user2",
            "url": "example.com/user2"
        }
    ]
......
......
......
Record10
     [
        {
            "id": "1",
            "firstname": "user10",
            "url": "example.com/user10"
        },
        {
            "id": "2",
            "firstname": "user1",
            "url": "example.com/user1"
        }
    ]


我运行的查询是:

Select internal_id from users_dummy where JSON_EXTRACT(user_friends, '$[0].url') = "example.com/user1" or JSON_EXTRACT(user_friends, '$[1].url') = "example.com/user1";


因此,o / p为:
Record1, Record10

这是在记录中搜索值的正确方法吗?
提前致谢。

最佳答案

您可以这样使用JSON_SEARCH

SELECT *
FROM users_dummy
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$[*].url') IS NOT NULL


demo on dbfiddle.uk

如果使用的是对象而不是数组,则可以使用以下解决方案:

SELECT *
FROM users_dummy
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$.*.url') IS NOT NULL


demo on dbfiddle.uk

关于mysql - 在MySQL中检索JSON数组内的Json数据的值,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/59973329/

10-12 01:46