java - 将Tango 3D投影到屏幕上的Google Project Tango

Ptoject Tango提供了一个点云，如何获得以米为单位的3D点在像素中的位置？

我尝试使用投影矩阵，但得到的值非常小（0.5、1.3等），而不是1234324（以像素为单位）。

我包括我尝试过的代码

    //Get the current rotation matrix
    Matrix4 projMatrix =  mRenderer.getCurrentCamera().getProjectionMatrix();



    //Get all the points in the pointcloud and store them as 3D points
    FloatBuffer pointsBuffer =  mPointCloudManager.updateAndGetLatestPointCloudRenderBuffer().floatBuffer;
    Vector3[] points3D = new Vector3[pointsBuffer.capacity()/3];

    int j =0;
    for (int i = 0; i < pointsBuffer.capacity() - 3; i = i + 3) {

        points3D[j]= new Vector3(
                pointsBuffer.get(i),
                pointsBuffer.get(i+1),
                pointsBuffer.get(i+2));
        //Log.v("Points3d", "J: "+ j + " X: " +points3D[j].x + "\tY: "+ points3D[j].y +"\tZ: "+ points3D[j].z );
        j++;
    }


    //Get the projection of the points in the screen.
    Vector3[] points2D = new Vector3[points3D.length];
    for(int i =0; i < points3D.length-1;i++)
    {
        Log.v("Points", "X: " +points3D[i].x + "\tY: "+ points3D[i].y +"\tZ: "+ points3D[i].z );
        points2D[i] = points3D[i].multiply(projMatrix);
        Log.v("Points", "pX: " +points2D[i].x + "\tpY: "+ points2D[i].y +"\tpZ: "+ points2D[i].z );
    }

我正在使用的示例是点云Java，可以在这里找到
https://github.com/googlesamples/tango-examples-java



更新

TangoCameraIntrinsics ccIntrinsics = mTango.getCameraIntrinsics(TangoCameraIntrinsics.TANGO_CAMERA_COLOR);
    double fx = ccIntrinsics.fx;
    double fy = ccIntrinsics.fy;
    double cx = ccIntrinsics.cx;
    double cy = ccIntrinsics.cy;

    double[][] projMatrix = new double[][] {
            {fx, 0 , -cx},
            {0,  fy, -cy},
            {0,  0,    1}
    };

然后计算投影点

for(int i =0; i < points3D.length-1;i++)
    {

        double[][] point = new double[][] {
                {points3D[i].x},
                {points3D[i].y},
                {points3D[i].z}
        };

        double [][] point2d = CustomMatrix.multiplyByMatrix(projMatrix, point);

        points2D[i] = new Vector2(0,0);
        if(point2d[2][0]!=0)
        {
            Log.v("temp point", "pX: " +point2d[0][0]/point2d[2][0]+" pY: " +point2d[1][0]/point2d[2][0] );
            points2D[i] = new Vector2(point2d[0][0]/point2d[2][0],point2d[1][0]/point2d[2][0]);
        }

    }

但是我认为结果仍然不是预期的，例如我得到的结果如下：

pX：-175.58042313027244 pY：-92.573740812066

对我来说看起来不对。



更新
按建议使用彩色摄像头可获得更好的效果，但点数仍为负值
-1127.8086915171814 pY：-652.5887102192332

将它们乘以-1是否可以？

最佳答案

您必须将3D点与RGB相机的本征矩阵相乘才能获得像素坐标。 3D点位于Depthcamera的框架中。您可以通过以下方法获得像素坐标：



和



x和y是像素坐标。
使用intrinsics函数用参数构造K

关于java - 将Tango 3D投影到屏幕上的Google Project Tango，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/34565930/