我创建了两个if语句放入链接列表中,并检查有多少个数字高于平均值,有多少个数字低于平均值。当我运行程序以理解时,if语句仅计算一个数字。另外,在程序运行时,仅调用一个if语句,而不是两个都调用。也许我忽略了什么?

double CalAverage (NewNumber *start){

int res;
double average = 0;
double total = 0;
int n = 1;
int x = 1;
int y = 1;

/*if (res != 1){
    fprintf(stderr, "Something bad happened in CalAverage()\n");
    return add;
}*/
while (start->next){
    average += start->newNum;
    start = start->next;
    ++n;
}
average += start->newNum;
total = average/n;
if(total < start->newNum){
        ++x;
        printf("Numbers greater than average: %d\n",x);
    }else if(total > start->newNum){
        ++y;
        printf("Numbers less than average: %d\n", y);
    }
printf("The average is: %lf\n",total);
return total;
return x;
return y;

}

最佳答案

首先,通过在while循环中重写指针,您将丢失指向列表开头的指针。在开始遍历之前,请将其复制到一旁。

第二,将if语句放入另一个循环中(重新分配列表的开头之后)以计算低于/高于平均值。

double CalAverage (NewNumber *start){

    double average = 0;
    double sum = 0;
    int n = 0;
    int x = 0;
    int y = 0;

    NewNumber *temp = start;

    while (temp){
        sum += temp->newNum;
        temp = temp->next;
        ++n;
    }

    average = sum / n;

    temp = start;

    while (temp){

        if(average < temp->newNum){
            ++x;
        }else if(average > temp->newNum){
            ++y;
        }

        temp = temp->next;
    }

    printf("The average is: %lf\n",average);
    printf("Numbers greater than average: %d\n",x);
    printf("Numbers less than average: %d\n", y);
    return average;
}

关于c - “CalAverage”函数中的if语句存在问题,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/39431408/

10-12 14:25
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