c++ - new >> 我如何将一个包含 3 列且每列包含 100 个数字的文件读取到一个数组中？

int exam1[100];// array that can hold 100 numbers for 1st column
int exam2[100];// array that can hold 100 numbers for 2nd column
int exam3[100];// array that can hold 100 numbers for 3rd column

int main()
{
  ifstream infile;

  int num;
  infile.open("example.txt");// file containing numbers in 3 columns
     if(infile.fail()) // checks to see if file opended
    {
      cout << "error" << endl;
    }
       while(!infile.eof()) // reads file to end of line
      {
         for(i=0;i<100;i++); // array numbers less than 100
           {
        while(infile >> [exam]); // while reading get 1st array or element
            ???// how will i go read the next number
            infile >> num;
          }
      }
  infile.close();
}

最佳答案

int exam1[100];// array that can hold 100 numbers for 1st column
int exam2[100];// array that can hold 100 numbers for 2nd column
int exam3[100];// array that can hold 100 numbers for 3rd column

int main() // int main NOT void main
{
  ifstream infile;

  int num = 0; // num must start at 0
  infile.open("example.txt");// file containing numbers in 3 columns
     if(infile.fail()) // checks to see if file opended
    {
      cout << "error" << endl;
      return 1; // no point continuing if the file didn't open...
    }
       while(!infile.eof()) // reads file to end of *file*, not line
      {
         infile >> exam1[num]; // read first column number
         infile >> exam2[num]; // read second column number
         infile >> exam3[num]; // read third column number

         ++num; // go to the next number

         // you can also do it on the same line like this:
         // infile >> exam1[num] >> exam2[num] >> exam3[num]; ++num;
      }
  infile.close();

  return 0; // everything went right.
}

我假设你每行总是有 3 个数字。如果您知道确切的行数，请将 while 替换为从 0 到行数的 for。

关于c++ - new >> 我如何将一个包含 3 列且每列包含 100 个数字的文件读取到一个数组中？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/2706076/