c# - 读者无法显示结果

我与数据库建立了连接，并且执行了查询以获取表中特定字段的结果，但是读者却没有输入一段时间，为什么？

 public void connect()
    {
        string connStr = @"Server=xx98.66;Port=xx6;Database=sxxt;Uid=axx;Pwd=admxxx3z;";
        MySqlConnection conn = new MySqlConnection(connStr);

        try
        {
            Console.WriteLine("Connecting to MySQL...");
            conn.Open();

            string stm = "SELECT lastUpdated from soccerseason WHERE caption = 'Eredivisie 2015/1'";
            MySqlCommand cmd = new MySqlCommand(stm, conn);

            MySqlDataReader rdr = cmd.ExecuteReader();

            while (rdr.Read())
            {
                Console.WriteLine("stdrstrr" + rdr.GetString(0));
            }

            Console.WriteLine("Connection successfull !");

            conn.Close();
            Console.ReadLine();
        }
        catch (Exception ex)
        {
            Console.WriteLine("Eccezione =>  " + ex.ToString());
        }
        Console.WriteLine("Done.");
    }
}

最佳答案

我认为这对您有帮助

包括这个

using MySql.Data.Common;
using MySql.Data.Types;
using MySql.Data.MySqlClient;

略微更改代码并检查

    {
         string connStr = @"Server=xx98.66;Port=xx6;Database=sxxt;Uid=axx;Pwd=admxxx3z;";
                MySqlConnection conn = new MySqlConnection(connStr);
        try
    {
         string stm = "SELECT lastUpdated from soccerseason WHERE caption = 'Eredivisie 2015/1'";

                    MySqlCommand cmd= conn.CreateCommand();
                    cmd.CommandText = @"SELECT lastUpdated from soccerseason WHERE caption = 'Eredivisie 2015/1'";
                    MySqlDataReader rdr;
                    conn.Open();
                    rdr= cmd.ExecuteReader();
                    DataTable dtsoccer= new DataTable();
                    dtsoccer.Load(rdr);
                    foreach (DataRow row in dtsoccer.Rows)
                    {
                        Console.WriteLine(row["lastUpdated "].ToString());
                    }
                    conn.Close();
                    Console.ReadKey();

      }
            catch (Exception ex)
            {
                Console.WriteLine("Eccezione =>  " + ex.ToString());
            }
            Console.WriteLine("Done.");
        }
    }