我创建了一种从普通字符串生成属性字符串的方法。下面的attrString值非空且内容正确。

运行我的应用程序后,第二行失败,并显示EXC_BAD_ACCESS。知道为什么吗?

__bridge_retained调用是iOS 5要求afaik。我也尝试过__bridge,但没有效果,问题仍然存在。

    NSMutableAttributedString *attrString = (NSMutableAttributedString*)[textLayer attributedString];
    CTFramesetterRef framesetter = CTFramesetterCreateWithAttributedString((__bridge_retained CFMutableAttributedStringRef)attrString);


更新

如果我做:

    NSMutableAttributedString *attrString = (NSMutableAttributedString*)[textLayer attributedString];
    NSLog(@"%@", attrString);
    CTFramesetterRef framesetter = CTFramesetterCreateWithAttributedString((__bridge CFMutableAttributedStringRef)attrString);


这样,NSLog行将无法编译; Xcode给出警告和错误,指出"Incompatible pointer types passing 'char[3]' to parameter of type 'NSString *'"

所以我尝试这样做:

    NSLog([attrString description]);


这给出了以下输出(出于隐私目的,我已将字符串内容替换为<snipped>):

2012-01-19 06:49:11.307 WritePath[2475:707] <Snipped>{ CTForegroundColor = "<CGColor 0x281530> [<CGColorSpace 0x22d1a0> (kCGColorSpaceDeviceRGB)] ( 0 0 0 1 )"; NSFont = "<CGFont (0x28f850): ArialMT>"; NSParagraphStyle = "CTParagraphStyle:\nwriting direction = -1, alignment = 3, line break mode = 0, default tab interval = 0\nfirst line head indent = 0, head indent = 0, tail indent = 0\nline height multiple = 0, maximum line height = 0, minimum line height = 0\nline spacing adjustment = 0, paragraph spacing = 0, paragraph spacing before = 0\ntabs:\n<CFArray 0x287b50 [0x3f229630]>{type = immutable, count = 12, values = (\n\t0 : CTTextTab: location = 28, alignment = 0, options = (none)\n\n\t1 : CTTextTab: location = 56, alignment = 0, options = (none)\n\n\t2 : CTTextTab: location = 84, alignment = 0, options = (none)\n\n\t3 : CTTextTab: location = 112, alignment = 0, options = (none)\n\n\t4 : CTTextTab: location = 140, alignment = 0, options = (none)\n\n\t5 : CTTextTab: location = 168, alignment = 0, options = (none)\n\n\t6 : CTTextTab: location = 196, alignment = 0, options = (none)\n\n\t7 : CTTextTab: location = 224, alignment = 0, options = (none)\n\n\t8 : CTTextTab: location = 252, alignment = 0, options = (none)\n\n\t9 : CTTextTab: location = 280, alignment = 0, options = (none)\n\n\t10 : CTTextTab: location = 308, alignment = 0, options = (none)\n\n\t11 : CTTextTab: location = 336, alignment = 0, options = (none)\n\n)}";}

最佳答案

我在属性字符串转储中注意到了这一点:

NSFont = "<CGFont (0x28f850): ArialMT>"


您是否使用CGFontRef作为kCTFontAttributeName键的值来创建属性字符串?您必须使用CTFontRef,而不是CGFontRef。他们是不同的。

10-08 20:22