我正在运行以下程序,但出现错误:
First-chance exception at 0x0f32d440 (msvcr100d.dll) in c.exe: 0xC0000005: Access violation reading location 0x00000000.
Unhandled exception at 0x772815de in c.exe: 0xC0000005: Access violation reading location 0x00000000.
The program '[9048] c.exe: Native' has exited with code -1073741510 (0xc000013a).
这是密码
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[], char *env[]) //char *argv[]
{
int i;
printf("These are the %d command- line arguments passed to main:\n\n", argc);
if(strcmp(argv[1],"123")==0)
{
printf("success\n");
}
else
for(i=0; i<=argc; i++)
//if(strcmp(argv[1],"abc")==0)
printf("argv[%d]:%s\n", i, argv[i]);
/*printf("\nThe environment string(s)on this system are:\n\n");
for(i=0; env[i]!=NULL; i++)
printf(" env[%d]:%s\n", i, env[i]);*/
system("pause");
}
问题应该是strcmp函数,但我不知道如何解决它。
有人能帮忙吗?
最佳答案
你至少有两个问题。
首先是这样做:
if(strcmp(argv[1],"123")==0)
不需要首先检查
argc >= 2
。其次是:
for(i=0; i<=argc; i++)
在这种情况下,您应该处理参数
0
到argc - 1
之间的包含参数。循环的作用是处理参数0
到argc
并且argv[argc]
总是NULL
。以下程序说明了解决此问题的一种方法:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main (int argc, char *argv[]) {
int i;
printf ("These are the %d command-line argument(s) passed to main:\n", argc);
if ((argc >= 2) && (strcmp (argv[1], "123") == 0)) {
printf (" success\n");
} else {
for (i = 0; i < argc; i++) {
printf (" argv[%d] = [%s]\n", i, argv[i]);
}
}
return 0;
}
您可以看到,只有在确保正确填充
"123"
之后,才能与argv[1]
进行比较。此外,循环已更改为排除argv[argc]
,因为这不是参数之一。抄本如下:pax> testprog
These are the 1 command-line argument(s) passed to main:
argv[0] = [testprog]
pax> testprog 123
These are the 2 command-line argument(s) passed to main:
success
pax> testprog a b c
These are the 4 command-line argument(s) passed to main:
argv[0] = [testprog]
argv[1] = [a]
argv[2] = [b]
argv[3] = [c]
关于c - 访问冲突读取位置0x00000000。与argv [],我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/16953512/