*仅供引用-我正在从事OOP入门项目。这似乎是一个基本问题,但我在任何地方都找不到清晰的解释。
我试图在调用作为其他对象的私有(private)数据成员的对象的成员函数时避免包装函数。下面,我简单地说明了我的意思。有一个顶级Game_Manager对象,其中包含2个Player对象,每个对象都包含一个Weapon对象。
Game_Manager知道玩家的武器应何时进攻。有什么方法可以避免Player中的包装器功能?这只是不好的设计吗?
class Weapon
{
public:
void attack();
};
class Player
{
public:
void attack()
{
weapon.attack();
}
private:
Weapon weapon;
};
class Game_Manager
{
public:
time_for_first_player_to_attack()
{
player_1.attack();
}
private:
Player player_1;
Player player_2;
};
最佳答案
也许
class Player
{
public:
Weapon getWeapon() { return weapon; } const;
private:
Weapon weapon;
};
class Game_Manager
{
public:
time_for_first_player_to_attack()
{
player_1.getWeapon().attack();
}
private:
Player player_1;
Player player_2;
};
关于c++ - 如何避免C++中类中的类的包装函数,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/19722429/