javascript - Action 必须具有type属性

我的效果似乎是引发Actions must have a type property，这似乎是导致问题的原因，但我的RegisterSuccess动作似乎是我所说的方式，因此我尝试了一些解决方案，但在我看来，它们似乎不起作用。

影响：

 @Effect()
    register = this.actions$.pipe(
        ofType(AuthActionTypes.REGISTER),
        switchMap(action => this.auth.register(action.registration).pipe(
            map(result => ([
                { type: AuthActionTypes.REGISTER_SUCCESS, user: result }
            ])),
            catchError(result => ([
                { type: AuthActionTypes.REGISTER_FAIL }
            ])),
        ))
    );

行动：

export class Register implements Action {
    readonly type = AuthActionTypes.REGISTER;
    constructor(public registration: Registration) {}
}

export class RegisterSuccess implements Action {
    readonly type = AuthActionTypes.REGISTER_SUCCESS;
    constructor(public user: User) {}
}

export class RegisterFail implements Action {
    readonly type = AuthActionTypes.REGISTER_FAIL;
    constructor() {}
}

服务：

register(user: Registration): Observable<any> {
        return this.api.post('auth/register', user).pipe(map(res => res.data));
    }

最佳答案

您的效果是针对NgRx版本8.3.0编写的
您的操作是针对NgRx版本7.4.0编写的

“ switchMap（action => this.auth.register（action.registration）.pipe（”
你这里不需要管道

对于NgRx版本8.3.0，应该是这样的：
行动：

import { createAction, props } from '@ngrx/store';
export const register = createAction(AuthActionTypes.REGISTER());
export const registerSuccess = createAction(AuthActionTypes.REGISTER_SUCCESS, props<{user: User}>());
export const registerFail = createAction(AuthActionTypes.REGISTER_FAIL);

效果：

@Effect()
    register = this.actions$.pipe(
        ofType(register.type),
        mergeMap(action => this.auth.register(action.registration),
        map(result => ({ type: registerSuccess.type, user: result })),
        catchError(result => ({ type: registerFail.type })),
        ))
    );