java - 混合8位8000 Hz PCM_MULAW样本的最简单方法是什么？

我想在Java中混合使用多个ULAW示例。有没有一种方法可以不转换为PCM？我试图做一个8000Hz 8bit VoIP应用程序。我对所有使用ULAW编码的AU文件(在goldwave中创建)进行了即时测试。我当前的实现是:

[码]

    AudioFormat f = new AudioFormat(AudioFormat.Encoding.PCM_SIGNED, 8000, 16, 1, 2, 8000, false);
    SourceDataLine sdl = AudioSystem.getSourceDataLine(f);
    sdl.open(f);
    sdl.start();

    File file1 = new File("C:\\Scream3.au");
    AudioInputStream ais1 = AudioSystem.getAudioInputStream(file1);
    AudioInputStream aisTarget1 = AudioSystem.getAudioInputStream(f, ais1);

    File file2 = new File("C:\\Blackout3.au");
    AudioInputStream ais2 = AudioSystem.getAudioInputStream(file2);
    AudioInputStream aisTarget2 = AudioSystem.getAudioInputStream(f, ais2);

    byte[] data = new byte[10000];
    int[] calc = new int[5000];
    AudioInputStream[] streams = {aisTarget1, aisTarget2};
    int count = streams.length + 1;
    while (true) {
        int r = -1;
        for (int i = 0; i < streams.length; i++) {
            r = streams[i].read(data, 0, data.length);
            if (r == -1) break;
            for (int j = 0; j < calc.length; j++) {
                int tempVal = ((data[j * 2 + 1] << 8) | (data[j * 2] & 0xFF));
                calc[j] += tempVal;
            }
        }
        for (int i = 0; i < calc.length; i++) {
            calc[i] /= count;
            data[i * 2 + 0] = (byte) (calc[i] & 0xFF);
            data[i * 2 + 1] = (byte) (calc[i] >> 8);
        }
        if (r == -1) break;
        sdl.write(data, 0, data.length);
    }

[/码]

如果无法直接混合ulaw样本并且必须转换为PCM，如何从PCM格式转换(AudioFormat.Encoding.PCM_SIGNED，8000 Hz，16bits，1通道，2字节帧大小，8000帧速率，小尾数)
到ULAW(8bit 8000Hz)。

我是否做类似的事情:
1)将WAVE header 写入字节流
2)将PCM数据写入字节流
3)使用AudioSystem.getAudioInputStream(byte stream)获取PCM AIS
4)使用AudioSystem.getAudioInputStream(ulawFormat，PCM AIS)获取ULAW目标AIS

任何帮助表示赞赏。

编辑:
尝试从Mu-LAW转换为PCM(尝试使用http://en.wikipedia.org/wiki/Ulaw中的方程式):

[码]

    AudioFormat f = new AudioFormat(AudioFormat.Encoding.PCM_SIGNED, 8000, 8, 1, 1, 8000, false);
    SourceDataLine sdl = AudioSystem.getSourceDataLine(f);
    sdl.open(f);
    sdl.start();
    File file1 = new File("C:\\scream3.au");
    FileInputStream fis = new FileInputStream(file1);
    // Skip header
    fis.skip(24);
    byte[] data = new byte[8196];

    while (true) {
        int r = fis.read(data, 0, data.length);
        if (r == -1) break;
        for (int i = 0; i < r; i++) {
            float y = ((float) data[i] / Byte.MAX_VALUE);
            float sample = -1.0f * (float) (Math.signum(y) * (1.0f / 255.0f) * (Math.pow(1 + 255, Math.abs(y)) - 1.0f));
            data[i] = (byte) (sample * Byte.MAX_VALUE);
        }
        sdl.write(data, 0, data.length);
    }
    sdl.drain();
    sdl.stop();
    sdl.close();
    fis.close();

[/码]

最佳答案

我将使用Wikipedia:μ-law algorithm中的公式手动将线性编码一次转换为线性编码。

示例代码(基于OP的代码):

float sample1 = Math.signum(y1)/255.0*(Math.pow(256, Math.abs(y1))-1);
float sample2 = Math.signum(y2)/255.0*(Math.pow(256, Math.abs(y2))-1);
float combined = somethig * sample1 + (1-something) * sample2;
float result = Math.signum(combined)*Math.log(1+255*Math.abs(combined))/Math.log(256);