如果必须计算点和多边形之间的最近距离(例如,点和湖(naturalearthdata.com)),则可以这样做(取自here):

...
LocationIndexedLine line = new LocationIndexedLine(((MultiPolygon)    feature.getDefaultGeometry()).getBoundary());
LinearLocation here = line.project(coordinate);
Coordinate point = line.extractPoint(here);
...


和:

      ...
      NearestPolygon polyFinder = new NearestPolygon(features);

      GeometryFactory gf = JTSFactoryFinder.getGeometryFactory();
      Point p = gf.createPoint(new Coordinate(-49.2462798, -16.7723987));

      Point pointOnLine = polyFinder.findNearestPolygon(p);
      if (!pointOnLine.isEmpty()) {
        System.out.println(pointOnLine + " is closest to " + p);
        SimpleFeature lastMatched2 = polyFinder.getLastMatched();
        String attribute = (String) lastMatched2.getAttribute("name");
        if(attribute.isEmpty()) {
          attribute = (String) lastMatched2.getAttribute("note");
        }
        if (((Geometry) (lastMatched2.getDefaultGeometry())).contains(p)) {
          System.out.println("is in lake " + attribute);
        } else {
          System.out.println("nearest lake is " + attribute);
        }
...


直到这里确定。

但是,如何找到点和海岸线之间的最近距离,海岸线是多线串而不是多边形。
或者,如果我有线串?

我应该采用哪种方法?LocationIndexedLineLinearLocation怎么办?

最佳答案

我认为您可以通过将行更改为:

LocationIndexedLine line = new LocationIndexedLine(((Geometry)
     feature.getDefaultGeometry()));


由于某种原因,getDefaultGeometry返回一个Object,因此您需要将其强制转换为有用的东西。

关于java - 多线串和点之间的距离,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/45144947/

10-10 08:41