你好,我有一长串。我想将其拆分为具有很多回头率的某种格式。
每行有5个简短的单词。
例如string input="'250.0','250.00','250.01','250.02','250.03','250.1','250.10','250.11','250.12','250.13','250.2','250.20','250.21','250.22','250.23','250.3','250.30','250.31','250.32','250.33','250.4','250.40','250.41','250.42','250.43','250.5','250.50','250.51','250.52','250.53','250.6','250.60','250.61','250.62','250.63','250.7','250.70','250.71','250.72','250.73','250.8','250.80','250.81','250.82','250.83','250.9','250.90','250.91','250.92','250.93','357.2','357.20','362.01','362.02','362.03','362.04','362.05','362.06','362.07','366.41','648.0','648.00','648.01','648.02','648.03','648.04'";
它有66个简短的单词。
string output = "'250.0','250.00','250.01','250.02','250.03',
'250.1','250.10','250.11','250.12','250.13',
'250.2','250.20','250.21','250.22','250.23',
'250.3','250.30','250.31','250.32','250.33',
'250.4','250.40','250.41','250.42','250.43',
'250.5','250.50','250.51','250.52','250.53',
'250.6','250.60','250.61','250.62','250.63',
'250.7','250.70','250.71','250.72','250.73',
'250.8','250.80','250.81','250.82','250.83',
'250.9','250.90','250.91','250.92','250.93',
'357.2','357.20','362.01','362.02','362.03',
'362.04','362.05','362.06','362.07','366.41',
'648.0','648.00','648.01','648.02','648.03',
'648.04'";
我以为我必须先在字符串中计算char',',例如the example中。但这可能有点笨拙。
谢谢你的建议。
最佳答案
如果我正确地理解了你,你想
用逗号分隔这些单词
将结果分组,每行包含5个单词
用Environment.NewLine
作为分隔符构建一个字符串
string input = "'250.0','250.00','250.01','250.02','250.03','250.1','250.10','250.11','250.12','250.13','250.2','250.20','250.21','250.22','250.23','250.3','250.30','250.31','250.32','250.33','250.4','250.40','250.41','250.42','250.43','250.5','250.50','250.51','250.52','250.53','250.6','250.60','250.61','250.62','250.63','250.7','250.70','250.71','250.72','250.73','250.8','250.80','250.81','250.82','250.83','250.9','250.90','250.91','250.92','250.93','357.2','357.20','362.01','362.02','362.03','362.04','362.05','362.06','362.07','366.41','648.0','648.00','648.01','648.02','648.03','648.04'";
int groupCount = 5;
var linesGroups = input.Split(',')
.Select((s, index) => new { str = s, Position = index / groupCount, Index = index })
.GroupBy(x => x.Position);
StringBuilder outputBuilder = new StringBuilder();
foreach (var grp in linesGroups)
{
outputBuilder.AppendLine(String.Join(",", grp.Select(x => x.str)));
}
String output = outputBuilder.ToString();
编辑:结果是:
'250.0','250.00','250.01','250.02','250.03'
'250.1','250.10','250.11','250.12','250.13'
'250.2','250.20','250.21','250.22','250.23'
'250.3','250.30','250.31','250.32','250.33'
'250.4','250.40','250.41','250.42','250.43'
'250.5','250.50','250.51','250.52','250.53'
'250.6','250.60','250.61','250.62','250.63'
'250.7','250.70','250.71','250.72','250.73'
'250.8','250.80','250.81','250.82','250.83'
'250.9','250.90','250.91','250.92','250.93'
'357.2','357.20','362.01','362.02','362.03'
'362.04','362.05','362.06','362.07','366.41'
'648.0','648.00','648.01','648.02','648.03'
'648.04'
如果要在每行后面添加逗号(例如您的示例):
foreach (var grp in linesGroups)
{
outputBuilder.AppendLine(String.Join(",", grp.Select(x => x.str)) + ",");
}
// remove last comma + Environment.NewLine
outputBuilder.Length -= ( 1 + Environment.NewLine.Length );
关于c# - 将长字符串拆分为自定义字符串,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/10500626/