我需要将'767f440128e1a00a'十六进制数据转换为打包的EBCDIC字符串。我希望将所有result
结果合并为一个字符串,但是python给出了Unicode错误UnicodeDecodeError: 'utf-8' codec can't decode byte 0xe1 in position 0: unexpected end of data
s='767f440128e1a00a'
output = []
DDF = [1]
distance = 0
for y in range (1,len(s[2:])):
for x in DDF:
if s[2:][distance:x*2+distance]!='':
output.append(s[2:][distance:x*2+distance])
else:
continue
distance += x*2
print(output)
final=[]
result=''
bytearrya=[]
for x in output:
result=(str(bytearray.fromhex(x).decode()))
x = codecs.decode(x, "hex")
final.append(x)
最佳答案
这是基于Python byte representation of a hex string that is EBCDIC的代码,其中提到“根据this,您需要使用'cp500'进行解码”
Codec / Aliases / Languages
cp500 / EBCDIC-CP-BE, EBCDIC-CP-CH, IBM500 / Western Europe
my_string_in_hex = '767f440128e1a00a'
my_bytes = bytearray.fromhex(my_string_in_hex)
print(my_bytes)
my_string = my_bytes.decode('cp500')
print(my_string)
输出: