我如何使用收集器以便将DAO列表转换为Map<String, List<Pojo>>
daoList看起来像这样:
[0] : id = "34234", team = "gools", name = "bob", type = "old"
[1] : id = "23423", team = "fool" , name = "sam", type = "new"
[2] : id = "34342", team = "gools" , name = "dan", type = "new"
我想对“团队”属性进行分组,并为每个团队提供一个列表,如下所示:
"gools":
["id": 34234, "name": "bob", "type": "old"],
["id": 34342, "name": "dan", "type": "new"]
"fool":
["id": 23423, "name": "sam", "type": "new"]
Pojo看起来像这样:
@Data
@NoArgsConstructor
@AllArgsConstructor(access = AccessLevel.PUBLIC)
public class Pojo{
private String id;
private String name;
private String type;
}
这就是我试图这样做的方式,显然是错误的方式:
public Team groupedByTeams(List<? extends GenericDAO> daoList)
{
Map<String, List<Pojo>> teamMap= daoList.stream()
.collect(Collectors.groupingBy(GenericDAO::getTeam))
}
最佳答案
您当前的收集器.collect(Collectors.groupingBy(GenericDAO::getTeam))
-正在生成Map<String,List<? extends GenericDAO>>
。
为了生成Map<String, List<Pojo>>
,您必须通过将GenericDAO
收集器链接到Pojo
收集器将Collectors.mapping()
实例转换为Collectors.groupingBy()
实例:
Map<String, List<Pojo>> teamMap =
daoList.stream()
.collect(Collectors.groupingBy(GenericDAO::getTeam,
Collectors.mapping (dao -> new Pojo(...),
Collectors.toList())));
假设您有一些
Pojo
构造函数,该构造函数接收GenericDAO
实例或相关的GenericDAO
属性。