我的代码如下,应该可以工作,但是由于某种原因,它无法在join语句中识别wm_stores.lat。有人有想法么?
SELECT wm_dcs.dc_id, wm_stores.store_id
FROM wm_dcs
JOIN wm_stores
ON wm_stores.lat BETWEEN wm_dcs.lat - (250.0 / 69.0)
AND wm_dcs.lat + (250.0 / 69.0)
AND wm_stores.lon BETWEEN wm_dcs.lon - (250.0 / (69.0 * COS(RADIANS(wm_dcs.lat))))
AND wm_dcs.lon + (250.0 / (69.0 * COS(RADIANS(wm_dcs.lat))))
AND (69.0 * DEGREES(ACOS(COS(RADIANS(wm_dcs.lat) * COS(RADIANS(stores.latitude))
* COS(RADIANS(dc.longitude - stores.longitude))
+ SIN(RADIANS(dc.latitude))
* SIN(RADIANS(wm_stores.lon)))))) <= 250.0;
不同版本的代码:
set @dc_lat = 40.811973 ;
set @dc_lon = -73.946299 ;
select wm_stores.store_id,
( 3959 * acos( cos( radians(@dc_lat) ) * cos( radians(wm_stores.lat ) )
* cos( radians( wm_stores.lon ) - radians(@dc_lon) ) + sin( radians(@dc_lat) )
* sin( radians( wm_stores.lat ) ) ) ) AS distance
from wm_stores
having distance <= 250
order by distance asc;
最佳答案
在您的查询中
SELECT wm_dcs.dc_id, wm_stores.store_id
FROM wm_dcs
JOIN wm_stores
ON wm_stores.lat BETWEEN wm_dcs.lat - (250.0 / 69.0)
AND wm_dcs.lat + (250.0 / 69.0)
AND wm_stores.lon BETWEEN wm_dcs.lon - (250.0 / (69.0 * COS(RADIANS(wm_dcs.lat))))
AND wm_dcs.lon + (250.0 / (69.0 * COS(RADIANS(wm_dcs.lat))))
AND (69.0 * DEGREES(ACOS(COS(RADIANS(wm_dcs.lat) * COS(RADIANS(stores.latitude))
* COS(RADIANS(dc.longitude - stores.longitude))
+ SIN(RADIANS(dc.latitude))
* SIN(RADIANS(wm_stores.lon)))))) <= 250.0;
我注意到没有像
stores
这样的表,但是您在查询中使用了stores.latitude
和stores.longitude
。可能是导致错误消息Unknown column 'stores.latitude' in 'on clause'
的原因。我建议您重新检查代码
AND (69.0 * DEGREES(ACOS(COS(RADIANS(wm_dcs.lat) * COS(RADIANS(stores.latitude))
* COS(RADIANS(dc.longitude - stores.longitude))
+ SIN(RADIANS(dc.latitude))
* SIN(RADIANS(wm_stores.lon)))))) <= 250.0;
关于mysql - 确定距离MySQL,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/40453555/