我得到的响应时间约为200毫秒。
我想对其进行更多优化。
我该如何实现?

CREATE OR REPLACE
PROCEDURE GETSTORES
(
LISTOFOFFERIDS IN VARCHAR2,
REF_OFFERS OUT TYPES.OFFER_RECORD_CURSOR
)
AS
BEGIN
  OPEN REF_OFFERS FOR
  SELECT
  /*+ PARALLEL(STORES 5) PARALLEL(MERCHANTOFFERS 5)*/
  MOFF.OFFERID,
  s.STOREID,
  S.LAT,
  s.LNG
  FROM
  MERCHANTOFFERS MOFF
  INNER JOIN STORES s ON MOFF.STOREID =S.STOREID
  WHERE
  MOFF.OFFERID IN
  (
    SELECT
      REGEXP_SUBSTR(LISTOFOFFERIDS,'[^,]+', 1, LEVEL)
    FROM
      DUAL CONNECT BY REGEXP_SUBSTR(LISTOFOFFERIDS, '[^,]+', 1, LEVEL) IS NOT NULL
  )
  ;
END
GETSTORES;

我正在使用regex_substr从LISTOFOFFERIDS中用逗号分隔的字符串中获取OfferID的列表。
我已经在Stores表的STOREID上创建了索引,但无济于事。
一种新的方法也可以做到这一点,如果它更快。

类型声明相同:
create or replace

    PACKAGE TYPES
    AS
    TYPE OFFER_RECORD
    IS
      RECORD(
      OFFER_ID MERCHANTOFFERS.OFFERID%TYPE,
      STORE_ID STORES.STOREID%TYPE,
      LAT STORES.LAT%TYPE,
      LNG STORES.LNG%TYPE
      );
    TYPE OFFER_RECORD_CURSOR
    IS
      REF
      CURSOR
        RETURN OFFER_RECORD;
      END
      TYPES;

选择计划揭示了以下信息:
Plan hash value: 1501040938

-------------------------------------------------------------------------------------------------------------
| Id  | Operation                                  | Name           | Rows  | Bytes | Cost (%CPU)| Time     |
-------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT                           |                |   276 | 67620 |    17  (12)| 00:00:01 |
|*  1 |  HASH JOIN                                 |                |   276 | 67620 |    17  (12)| 00:00:01 |
|   2 |   NESTED LOOPS                             |                |       |       |            |          |
|   3 |    NESTED LOOPS                            |                |   276 | 61272 |     3  (34)| 00:00:01 |
|   4 |     VIEW                                   | VW_NSO_1       |     1 |   202 |     3  (34)| 00:00:01 |
|   5 |      HASH UNIQUE                           |                |     1 |       |     3  (34)| 00:00:01 |
|*  6 |       CONNECT BY WITHOUT FILTERING (UNIQUE)|                |       |       |            |          |
|   7 |        FAST DUAL                           |                |     1 |       |     2   (0)| 00:00:01 |
|*  8 |     INDEX RANGE SCAN                       | OFFERID_INDEX  |   276 |       |     0   (0)| 00:00:01 |
|   9 |    TABLE ACCESS BY INDEX ROWID             | MERCHANTOFFERS |   276 |  5520 |     0   (0)| 00:00:01 |
|  10 |   TABLE ACCESS FULL                        | STORES         |  9947 |   223K|    13   (0)| 00:00:01 |
-------------------------------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - access("MERCHANTOFFERS"."STOREID"="STORES"."STOREID")
   6 - filter( REGEXP_SUBSTR ('M1-Off2,M2-Off5,M2-Off9,M5-Off4,M10-Off1,M1-Off3,M2-Off4,M3-Off2,M4-Of
              f6,M5-Off1,M6-Off1,M8-Off1,M7-Off3,M1-Off1,M2-Off1,M3-Off1,M3-Off4,M3-Off5,M3-Off6,M4-Off1,M4-Off7,M2
              -Off2,M3-Off3,M5-Off2,M7-Off1,M7-Off2,M1-Off7,M2-Off3,M3-Off7,M5-Off5,M4-Off2,M4-Off3,M4-Off5,M8-Off2
              ,M6-Off2,M1-Off5,M1-Off6,M1-Off9,M1-Off8,M2-Off6,M2-Off7,M4-Off4,M9-Off1,M6-Off4,M1-Off4,M1-Off10,M2-
              Off8,M3-Off8,M6-Off3,M5-Off3','[^,]+',1,LEVEL) IS NOT NULL)
   8 - access("MERCHANTOFFERS"."OFFERID"="$kkqu_col_1")

最佳答案

  • (如果服务器支持)(似乎需要),请将提示更改为/*+ PARALLEL(S 8) PARALLEL(MOFF 8)*/。当您有别名时,必须在提示中使用别名。
  • 您应该尝试APC(STORES(STOREID, LAT, LNG))
  • 建议的复合索引
  • 请回答以下问题:对于给出的示例,您在STORES表中获得了多少个不同的商店(select count(distinct storeid) from (your_query)),以及多少个商店? (Select count(*) from Stores)?
  • 您是否使用dbms_stats.gather_table_stats分析了表?
  • 我相信connect by查询不是问题。它在0.02秒内运行。
  • 10-07 23:50