list1 转换为 list2 以及将 list2 转换为 list1 的最优雅的方法是什么?

list1<- c('a','b','c','d','e','f','g','h','i')
list2<- c('abc','def','ghi')

即:以三组为一组接触元素。

感谢:D

最佳答案

list1 <- letters[1:10] (显示当向量的长度不是 3 的倍数时它是如何工作的)。然后,试试这个:

列表 1 到列表 2

# method 1 (seems to be the fastest so far,
# my suspicions about loop being slower were wrong)
list2 <- sapply(split(list1, (seq_along(list1)-1) %/% 3), paste, collapse = "")
# alternatively as @flodel mentions
list2 <- tapply(list1, (seq_along(list1)-1) %/% 3, paste, collapse = "")
tapply 版本的运行时间与 sapply+split 相似(未显示基准测试)。

更进一步,在 this post 中使用 @JoshOBrien 的想法
# method 2
pattern <- "(?<=[[:alnum:]]{3})(?=[[:alnum:]])"
strsplit(paste(list1, collapse=""), pattern, perl=TRUE)[[1]]
# [1] "abc" "def" "ghi" "j"

如果您想将最后一部分连接到最后一部分(此处是 jghi ),请执行以下操作:
pattern <- "(?<=[[:alnum:]]{3})(?=[[:alnum:]]{3})"
strsplit(paste(list1, collapse=""), pattern, perl=TRUE)[[1]]
# [1] "abc"  "def"  "ghij"

列表 2 到列表 1
unlist(strsplit(list2, ""), use.names=FALSE)
#  [1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j"

这是 method1method2 和 eddi 的基准测试:

数据:
list1 <- sample(letters, 1e5, replace=TRUE)

职能:
arun <- function() {
    pattern <- "(?<=[[:alnum:]]{3})(?=[[:alnum:]])"
    strsplit(paste(list1, collapse=""), pattern, perl=TRUE)[[1]]
}

arun2 <- function() {
    unname(sapply(split(list1, (seq_along(list1)-1) %/% 3), paste, collapse = ""))
}

eddi <- function() {
    substring(paste(list1, collapse = ""),
          seq(1, length(list1), 3),
          pmin(seq(3, length(list1)+2, 3), length(list1)))
}

基准测试:
require(microbenchmark)
microbenchmark(t1 <- arun(), t2 <- eddi(), t3 <- arun2(), times=10)
identical(t1, t2) # TRUE
identical(t1, t3) # TRUE

# Unit: milliseconds
#           expr       min        lq    median        uq       max neval
#   t1 <- arun() 3352.9867 3400.8627 3512.7037 3585.6499 3635.2182    10
#   t2 <- eddi() 3302.0925 3318.4184 3356.2109 3409.9728 3487.7220    10
#  t3 <- arun2()  474.9235  494.7407  539.4406  641.2605  907.9072    10

关于r - 连接组中的向量元素,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/16407782/

10-13 07:24