我有两个类:OuterClass和InnerClass。 InnerClass是OuterClass的私有成员,应该在OuterClass构造函数中使用InnerClass(int)构造函数创建,但是仍会调用默认的InnerClass构造函数。
InnerClass.hpp:
#ifndef INNERCLASS_HPP_
#define INNERCLASS_HPP_
class InnerClass {
public:
int a;
InnerClass();
InnerClass(int);
~InnerClass();
};
#endif /* INNERCLASS_HPP_ */
InnerClass.cpp:
#include "InnerClass.hpp"
#include <iostream>
InnerClass::InnerClass() {
a = 1;
std::cout << "inner class constructed, a = " << a << std::endl;
}
InnerClass::InnerClass(int x) {
a = x;
std::cout << "inner class constructed, a = " << a << std::endl;
//automatically: object InnerClass (a=3) is destroyed here...
}
InnerClass::~InnerClass() {
std::cout << "inner class destructed, a = " << a << std::endl;
}
OuterClass.hpp:
#ifndef OUTERCLASS_HPP_
#define OUTERCLASS_HPP_
#include "InnerClass.hpp"
class OuterClass {
private:
InnerClass blah;
public:
OuterClass();
~OuterClass();
void doSth();
};
#endif /* OUTERCLASS_HPP_ */
OuterClass.cpp:
#include "OuterClass.hpp"
#include <iostream>
OuterClass::OuterClass() {
// automatically: blah = InnerClass();
std::cout << "outer class constructing started, blah.a = " << blah.a << std::endl;
blah = InnerClass(3);
std::cout << "outer class constructed" << std::endl;
}
OuterClass::~OuterClass() {
std::cout << "outer class destructed" << std::endl;
}
void OuterClass::doSth() {
std::cout << "doSth: " << blah.a << std::endl;
}
主要:
#include "OuterClass.hpp"
#include <iostream>
int main(int argc, char** argv) {
std::cout << "Compiled at " << __TIME__ << std::endl;
OuterClass x = OuterClass();
x.doSth();
std::cout << "done" << std::endl;
}
输出:
Compiled at 12:11:12
inner class constructed, a = 1 //this is unexpected
outer class constructing started, blah.a = 1 //this should be random data
inner class constructed, a = 3
inner class destructed, a = 3 //this is unexpected
outer class constructed
doSth: 3
done
outer class destructed
inner class destructed, a = 3
问题:
为什么在OuterClass构造函数的开头调用InnerClass的默认构造函数?
什么和为什么在OuterClass构造函数中被破坏(“内部类被破坏,a = 3 //这是意外的”)?
看来a = 3的InnerClass对象在OuterClass构造函数中被破坏了,为什么方法doSth()返回3而不是随机数据呢?
为什么从InnerClass.hpp和InnerClass.cpp文件中删除InnerClass()构造函数会导致OuterClass.cpp文件中OuterClass构造函数的编译时错误?该错误表明未找到InnerClass()定义。
最佳答案
在构造函数中使用initializer-list。
OuterClass::OuterClass() : blah(3) {
// automatically: blah = InnerClass();
std::cout << "outer class constructing started, blah.a = " << blah.a << std::endl;
std::cout << "outer class constructed" << std::endl;
}
自从您使用
OuterClass::OuterClass() {
// automatically: blah = InnerClass();
std::cout << "outer class constructing started, blah.a = " << blah.a << std::endl;
blah = InnerClass(3);
std::cout << "outer class constructed" << std::endl;
}
首先,对于初始化,blah将被称为默认c-tor,在
blah = InnerClass(3);
中,它将创建临时对象并将其复制到blah,此字符串将被称为临时对象的析构函数。