我试图构建一个使用来自用户的输入的小程序,然后使用开关盒执行适合用户输入的操作。
我一直在努力寻找我的程序有什么问题,但没有运气很明显我少了一些东西。
这是密码,你能帮我找出它的毛病吗?
#include <stdio.h>
#define A 8.5
#define B 7.6
#define C 7.7
#define D 7.7
int main ()
{
char fuel;
float amount,total;
printf("please enter the desired fuel\n");
scanf_s("%c",&fuel);
switch(fuel)
{
case 'A' :
printf("how many liters of fuel do you want?\n");
scanf_s("%f",&amount);
total=amount*A;
if(total>150)
{
printf("the total price to pay is %.3f: \nYou have won a newspaper", total);
}
else
printf("the total price to pay is %.3f", total);
break;
case 'B' :
printf("how many liters of fuel do you want?\n");
scanf_s("%f",&amount);
total=amount*B;
if(total>150)
printf("the total price to pay is %f: \nYou have won a newspaper", total);
else
printf("the total price to pay is %.3f", total);
break;
case 'C' :
printf("how many liters of fuel do you want?\n");
scanf_s("%f",&amount);
total=amount*C;
if(total>150)
printf("the total price to pay is %f: \nYou have won a newspaper", total);
else
printf("the total price to pay is %.3f", total);
break;
case 'D' :
printf("how many liters of fuel do you want?\n");
scanf_s("%f",&amount);
total=amount*D;
if(total>150)
printf("the total price to pay is %f: \nYou have won a newspaper", total);
else
printf("the total price to pay is %f", total);
break;
default:
printf("no\n");
break;
}
}
即使当我输入“A”、“B”、“C”或“D”时,它也会变为默认值,而不是适当的情况。
谢谢你的帮助。
最佳答案
您没有正确使用scanf_s
函数。根据其documentation:
与scanf和wscanf不同,scanf和wscanf需要缓冲区大小
为c、c、s、s或字符串类型的所有输入参数指定
包含在[]中的控件集以字符为单位的缓冲区大小为
作为附加参数传递,紧跟在指向
缓冲区或变量
还应检查错误,因此应:
char fuel;
if (scanf_s("%c", &fuel, 1) != 1) {
puts("Error from scanf_s");
return 1;
}
关于c - 该程序将跳过所有切换情况下的情况,并转到默认情况,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33890402/